Since absolute value is just taking the positive value of whatever you put in the function, it is 7.8 as well. Also, absolute value can be described as the distance from 0 on the number line. 7.8 is 7.8 "units" away from 0, thus meaning it is equal to 7.8.
First to find the median we need to put the numbers in order from least to greatest.
62, 64, 65, 66, 67, 69, 83
Now take a number from each side
64, 65, 66, 67, 69
Once again.
65, 66, 67
On last time
66
So the median is 66.
Now to find the mean we must add all the numbers up
64+67+83+65+66+62+69
which equals 476
Now divide 476 by the total number of heights which is 7
476/7=68
So the mean is 68
Answers: Mean; 68 Median; 66
Alright, lets get started.
The foreign exchange rate between the japanese yen and the euro is 190:1 given.
It means 1 euro = 190 yen
We are asked to find how many yen will be equal to 10 euros.
Means we need to multiply given euros with 190 because 1 euro = 190 yen
Hence 10 euros 
yen
10 euros = 1900 yen : Answer
Hope it will help :)
Answer:
the probability that the average diameter of those sand dollars is more than 4.73 centimeters is 0.5910
Step-by-step explanation:
Given information:
mean, x = 5
standard deviation, σ = 0.9
number of sample, n = 16
now we calculate the probability that the average diameter of those sand dollars is more than 4.73 centimeters.
P(x>4.73) = P (z > (4.73 - x) / (σ 
)
= P (z > (4.73 - 4) / (0.9 
)
= P (z > 0.203)
= 0.5910
Answer:
99.85%
Step-by-step explanation:
The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.4 years; the standard deviation is 1.9 years.
Use the empirical rule (68-95-99.7%) to estimate the probability of a meerkat living less than 16.1 years.
Solution:
The empirical rule states that for a normal distribution most of the data fall within three standard deviations (σ) of the mean (µ). That is 68% of the data falls within the first standard deviation (µ ± σ), 95% falls within the first two standard deviations (µ ± 2σ), and 99.7% falls within the first three standard deviations (µ ± 3σ).
Therefore:
68% falls within (10.4 ± 1.9). 68% falls within 8.5 years to 12.3 years
95% falls within (10.4 ± 2*1.9). 95% falls within 6.6 years to 14.2 years
99.7% falls within (10.4 ± 3*1.9). 68% falls within 4.7 years to 16.1 years
Probability of a meerkat living less than 16.1 years = 100% - (100% - 99.7%)/2 = 100% - 0.15% = 99.85%
