Answer:
d
Step-by-step explanation:
just took the test
Answer:4
Step-by-step explanation:i cant rlly explain
Answer:
B - Her monthly average would have increased by $19.57. ... Katie works as a waitress and records her monthly tips in the table shown below. If Katie decided not to work the month of November, how would her five month average compare to her six month ... Lisa is currently taking physics as one of her electives in school.
Step-by-step explanation:
Answer:
269
Step-by-step explanation:
The margin of Error is E = 0.05
The level of significance is, α = 1 - confidence level = 1 - 0.9 = 0.1
Assume that the proportion is, p =0.5
From the standard normal table, observe that the critical value of Z for two tail test and 10% level of significance is 1.64
The calculation of sample size is as follows: n = (Z/E)²p(1-p)
n = (1.64/0.05)²0.5 (1 - 0.5)
n = (1.64/0.05)² 0.25
n = 1075.84 × 0.25
n = 268.96 ≈ 269
The required sample size with the given margin of error approximately is 269. This value indicates the size of the customers who are using this company’s products.
The answer:
<span>the upper and lower control limits (uclim and lclim) for mean formula is
for the mean chart
uclim= x+A2xR
where x = sum(of the value) / number of each value
and for
lclim=</span>x+A2xR
<span>
R is the range such that R= Xmax - Xmin
in the case of the sample 1: S1
the data are:
79.2 78.8 80.0 78.4 81.0
the mean is x1 = (</span>79.2 + 78.8 + 80.0 + 78.4 + 81.0) / 5= 79.48
<span>its range is R 1= 81.0 -78.4 = 2.6
we can do the same method for finding the mean chart and range for all samples
</span>S2: x2=<span> 80.14 , R2=2.3
</span>S3: x3= 80.14 , R3=1.2
S4: x4= 79.60 , R4=1.7
S5: x5= 80.02 , R5=2.0
S6: x6=80.38 , R6=1.4
<span>
therefore the average value is X= sum( x1+x2+...+x6) / 6 = 79.96
and R=sum(R1+R2+...+R6)/6=1.87
finally
range chart uclim =D4xR=3.95 and lclim is always equal to 0, because D3=0
we can say that the process is not in control.
</span>
