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neonofarm [45]
2 years ago
13

The "normal" high temperature for a June day in Albemarle is $82^\circ$ (degrees Fahrenheit). Last year, the first ten days of J

une were unusually hot, with highs of $84^\circ,$ $88^\circ,$ $91^\circ,$ $92^\circ,$ $96^\circ,$ $94^\circ,$ $89^\circ,$ $78^\circ,$ $87^\circ,$ and $81^\circ$. How many degrees above normal was the average high for that 10-day period?
Mathematics
1 answer:
crimeas [40]2 years ago
8 0

Answer:

6° F

Step-by-step explanation:

To get average of 10 days highs, we need to add all and divide by 10.

Average = \frac{84+88+91+92+96+94+89+78+87+81}{10}\\=\frac{880}{10}\\=88

And, the normal high temp is given as 82.

<em>How much higher is 88 than 82??</em>

<em />

It is 88 - 82 = 6°F above

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Four students wrote sequences during math class. Andre mc011-1.jpg Brenda mc011-2.jpg Camille mc011-3.jpg Doug mc011-4.jpg Which
maks197457 [2]
<span>A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.

</span>The common ration is obtained by dividing the a term by the preceding term.

Given that f<span>our students wrote sequences during math class with
Andre writing -\frac{3}{4} ,\frac{3}{8} ,-\frac{3}{16} ,-\frac{3}{32} , . . .
Brenda writing </span>\frac{3}{4} ,-\frac{3}{8} ,\frac{3}{16} ,\frac{3}{32} , . . .
Camille writing \frac{3}{4} ,\frac{3}{8} ,-\frac{3}{16} ,-\frac{3}{32} , . . .
Doug writing \frac{3}{4} ,-\frac{3}{8} ,\frac{3}{16} ,-\frac{3}{32} , . . .

Notice that the common ratio for the four students is - \frac{1}{2}.

For Andre, the last term is wrong and hence his sequence is not a geometric sequence.
For Brenda, the last term is wrong and hence her sequence is not a geometric sequence.
For Camille, her sequence is not a geometric sequence.
For Doug, his sequence is a geometric sequence with a common ratio of - \frac{1}{2}.

Therefore, Doug wrote a geometric sequence.
8 0
2 years ago
Read 2 more answers
In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t
victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The probability that he or she would choose the pair of socks in the center position is   p =\frac{1}{5}

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5  

b

The mean is  \mu = 20

The standard deviation is \sigma=4

c

The probability, P =0.0002

d

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability Pe = 0.0003

The probabilities P \approx Pe

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

                  p =\frac{1}{5}

                    =0.2

The mean of this distribution is mathematical represented as

           \mu = np

substituting the value

         \mu = 100 * 0.2

             \mu = 20

The standard deviation is mathematically represented as

         \sigma = \sqrt{np (1-p)}

substituting the value

           = \sqrt{100 * 0,2 (1-0.2)}

           \sigma=4

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

               P=P(X \ge 34 )

By standardizing the normal approximation we have that

              P(X \ge 34) \approx P(Z \ge z)

Now z is mathematically evaluated as

               z = \frac{x-\mu}{\sigma }

Substituting values

             z = \frac{34-20}{4}

               =3.5

So  using the z table the P(Z \ge 3.5) is  0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small  So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

 

6 0
2 years ago
A rectangle has an area of 256 cm 2 . it has a width that is 48 cm shorter than 4 times its length. what is the rectangle's leng
AveGali [126]
Let
x--------> <span>the rectangle's length
y-------> </span><span>the rectangle's width

we now that
Area of rectangle=x*y
Area=256 cm</span>²
<span>256=x*y-------> equation 1

y=4x-48------> y=4x-48------> equation 2

substitute equation 2 in equation 1

256=x*[4x-48]-----> 256=4x</span>²-48x
4x²-48x-256=0
<span>
using  a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=16 cm
y=4x-48----> y=4*16-48-----> y=16 cm

is a square

the answer is
</span>the rectangle's length is 16 cm

8 0
2 years ago
Select the term that does NOT describe the triangle. Select all that apply
emmainna [20.7K]

Answer:

this isnt an isosceles.

3 0
2 years ago
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0.2x + (-0.9) + 1.7 = 9.6<br> 0.2x + 0.8 = 9.6<br> X= <br> WHAT DOES x =
Andru [333]

Answer:

x =44

Step-by-step explanation:

0.2x + (-0.9) + 1.7 = 9.6

Combine like terms

.2x +.8 = 9.6

Subtract .8 from each side

.2x +.8 -.8 = 9.6 -.8

.2x = 8.8

Divide each side by .2

.2x/.2 = 8.8/.2

x =44

3 0
2 years ago
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