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Alekssandra [29.7K]
2 years ago
6

1. Factor each of the following completely. Look carefully at the structure of each quadratic function and consider the best way

to factor. Is there a GCF? Is it an example of a special case? SHOW YOUR WORK

Mathematics
1 answer:
kvasek [131]2 years ago
4 0

Answer: 1) (x - 7)(x - 8)

               2) 2x(2x-7)(x + 2)

               3) (4x + 7)²

               4) (9ab² - c³)(9ab² + c³)

<u>Step-by-step explanation:</u>

1) x² - 15x + 56  → use standard form for factoring

                    ∧

                -7 + -8 = -15

  (x - 7) (x - 8)

************************************

2) 4x³ - 6x² - 28x      → factor out the GCF (2x)

2x(2x² - 3x - 14)         → factor using grouping

2x[2x² + 4x    - 7x - 14]    

2x[ 2x(<u>x + 2</u>)   -7(<u>x + 2</u>)]

2x(2x - 7)(x + 2)

*************************************

3) 16x² + 56x + 49     → this is the sum of squares

√(16x²) = 4x      √(49) = 7

              (4x + 7)²

******************************************************

4) 81a²b⁴ - c⁶          → this is the difference of squares

√(81a²b⁴) = 9ab²       √(c⁶) = c³

       (9ab² - c³)(9ab² + c³)

   

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2 years ago
the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev
Naya [18.7K]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 16}{2.1}

Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

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A sociologist wishes to estimate the average number of automobile thefts in a large city per day within 2 automobiles. He wishes
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Answer:

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So the answer for this case would be n=30 rounded up to the nearest integer

Step-by-step explanation:

Information given

ME = 2 the margin of error desired

\sigma =4.2 standard deviation from previous studies

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =2 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance level is \alpha=0.01 and the critical value would be z_{\alpha/2}=2.58, replacing into formula (b) we got:

n=(\frac{2.58(4.2)}{2})^2 =29.35 \approx 30

So the answer for this case would be n=30 rounded up to the nearest integer

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Answer:

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Therefore, the regression equation for the winter rainy days is "Humidity = (β0 + β5) + β1Temperature".

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The maximum height of the baseball. Hope this helped :) 
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2 years ago
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