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2 years ago

A quarter is approximately 0.07 inches thick. A dollar bill is approximately 4.3 × 10-3 inches thick.

Mathematics

1 answer:

nlexa [21]2 years ago

8 0

Answer:

m = 6.57 and n = -2

Step-by-step explanation:

To answer this question you will covert the thickness of a dollar to standard notation and then compare the two values.

0.07 =compared to 0.0043 = 0.0657

0.0657 = 6.57 x 10^-2

A quarter is thicker than a dollar by 6.57 x 10^-2.

m = 6.57 and n = -2

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scholastic books sells 4 times as many textbooks as keller publishing; together they sold 7,775 textbooks. how many did scholast

sashaice [31]

Let us assume the number of text books sold by <span>keller publishing = x
Then
Then </span>number of text books sold by <span>Scholastic books = 4x
The total number of text books sold = 7775
Then
x + 4x = 7775
5x = 7775
x = 1555
Then
The nu</span>mber of text books sold by Scholastic books = 4x
= 4 * 1555
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I hope the procedure is clear enough for you to understand.

4 0

2 years ago

Company A charges $331.35 per week for a compact car with unlimited miles. Company B charges $175 per week plus $0.53 per mile,

Vladimir [108]

Answer:

Company A is a better deal than Company B for the number of miles greater than 295 miles

Step-by-step explanation:

Let

y ----> the charge per week in dollars

x ----> the number of miles

we have

<em>Company A</em>

$y=331.35$ -----> equation A

<em>Company B</em>

$y=0.53x+175$ -----> equation B

Solve the system by substitution

Equate equation A and equation B and solve for x

$331.35=0.53x+175$

$0.53x=331.35-175\\0.53x=156.35\\x=295\ mi$

For x=295 miles the charge in Company A and Company B is the same

therefore

Company A is a better deal than Company B for the number of miles greater than 295 miles

5 0

2 years ago

In Virginia, 120 lame dogs were tested for arthritis and Lyme disease. The results showed that 42 of the dogs had Lyme disease,

miskamm [114]

Answer:

The number of dogs that had both Lyme disease and arthritis is 18

Step-by-step explanation:

Let x represent dogs that have both Lyme disease and arthritis

Dog with only Lyme disease = 42 - x

Dog with only arthritis = 96 - x

The sum of the 3 category should give 120

x + (42 - x) + (96 - x) = 120

Collect like terms and solve

x - x - x + 42 + 96 = 120

-x + 138 = 120

138 - 120 = x

x = 18

Dog with only Lyme disease = 42 - x = 42 - 18 = 24

Dog with only arthritis = 96 - x = 96 - 18 = 78

Therefore, the number of dogs with both Lyme disease and anthritis is 18.

4 0

2 years ago

Which linear inequality will not have a shared solution set with the graphed linear inequality? y < Five-thirdsx – 2 y < N

elena-14-01-66 [18.8K]

Answer:

the third option

Step-by-step explanation:

idk :/

8 0

2 years ago

Read 2 more answers

Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units. Which statements bes

valentinak56 [21]

Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.

By the definition of rhombus, diagonals meet at right angles.

Implies that PQ = QA

x+2 = 3x - 14

x-3x=-14-2

-2x=-16

2x = 16

dividing by 2 on both sides, we will get,

$x =\frac{16}{2}$

<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>

The line segment $\overrightarrow{PA}=\overrightarrow{PQ}+\overrightarrow{QA}$