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Sliva [168]
2 years ago
12

A plane took a Navy Seal to a height of 10,000 feet above sea level. The Navy Seal jumped out of the plane and parachuted into t

he sea 10,000 feet down. Once in the sea, the Navy Seal dove 100 feet down before rising back up 25 feet. What is the Navy Seal's current depth?
Mathematics
2 answers:
Sav [38]2 years ago
8 0
The Navy Seal is currently 75 ft under water.
liberstina [14]2 years ago
4 0

Answer:

read the top one

Step-by-step explanation:

scroll up look and pay

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Write the expanded form of h(3k-12.4)
ExtremeBDS [4]

Answer:3hk - 12.4h

Step-by-step explanation:

h(3k-12.4)

h x 3k - h x 12.4

3hk - 12.4h

3 0
2 years ago
The figure below shows a line graph and two shaded triangles that are similar:Which statement about the slope of the line is tru
zzz [600]
Here is something to keep in mind. 
when there is a downward slope, the slope will ALWAYS have a negative slope. even if it is above the x-axis. negative slopes will tend to go from positive y-axis to negative y-axis 
so personally would have to go with -4
because the x-axis is by 4 each time. and this slope is going downward. 

your answer will be D

6 0
2 years ago
Read 2 more answers
Acasa Insurance Company offers several plans for home insurance.
astraxan [27]

The answer is -500, hope this helped

5 0
2 years ago
3. What unit would you use to measure the weight of a school bus? *
larisa [96]

Answer:

Tons

Step-by-step explanation:

A school bus should be weighed in tons due to the fact that it definitely weighs more than a few pounds.

4 0
2 years ago
Sarah’s stands on a ground and sights the top of a steep Clift at a 60 degree angle of elevation she then steps back 50 meters t
SashulF [63]

Answer:

Cliff is 45 m tall.

Step-by-step explanation:

Given:

Height of Sarah = 1.8 m

Angle of elevation = 60°

Angle of elevation 50 m back = 30°

As shown in the figure we have two right angled triangles SPQ and SPR.

Let the height of the cliff be h meters and h= h_1+h_s.

Using trigonometric ratios:

tan (Ф) = opposite/adjacent

In ΔSPQ.                                        In ΔSPR.

⇒ tan(60) = \frac{h_1}{x} ...equation (i)        ⇒ tan (30)=\frac{h_1}{x+50}  ...equation (ii)

Dividing equation (i) and (ii)

⇒ \frac{tan(60)}{tan(30)} = \frac{h_1}{x} \times \frac{x+50}{h_1}

⇒ 3 = \frac{x+50}{x}

⇒ 3x=x+50

⇒ 3x-x=50

⇒ 2x=50

⇒ x=\frac{50}{2}

⇒ x=25 meters

To find h_1 plugging x=25 in equation (i)

⇒ h_1=x\times tan(60)

⇒ h_1=25\times 1.73

⇒ h_1=43.25 meters

The height of the cliff from ground :

⇒ h= h_1+h_s

⇒ h= 43.25+1.8

⇒ h=45.05 meters

The cliff is 45 m tall to the nearest meter.

8 0
2 years ago
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