1. The first step is to realize you need to find a number that will be bigger than 74.
2. All you have to do for this problem is to divide 74 by 90%. You can put this in the calculator by typing in (74 / .9).
3. The answer you get should be 82.22
4. You can check this by multiplying 82.22 by 90%, and it should bring you back to 74.
When you have ratios and some unknowns you can create complex fractions from them.Bring them to the same denominator and solve for X.
Answer:
6° F
Step-by-step explanation:
To get average of 10 days highs, we need to add all and divide by 10.
Average = 
And, the normal high temp is given as 82.
<em>How much higher is 88 than 82??</em>
<em />
It is 88 - 82 = 6°F above
In order to construct this equation, we will use the variables:
V to represent mixture volume (40 ml)
C to represent mixture concentration (0.32)
v₁ to represent volume of first solution (40 / 4 = 10 ml)
c₁ to represent concentration of first solution (0.2)
v₂ to represent the volume of the second solution (40 * 3/4 = 30 ml)
c₂ to represent the concentration of the second solution
We know that the total amount of substance, product of the volume and concentration, in the final solution is equal to the individual amounts in the two given solutions. Thus:
VC = v₁c₁ + v₂c₂
40(0.32) = 10(0.2) + 30c
Answer:
25 : 1
Step-by-step explanation:
The diameter of the football is 5 times the diameter of the cricket ball. This means that the radius of the football is also 5 times the radius of the cricket ball.
Let the radius of the football be R.
Let the radius of the cricket ball be r.
This implies that:
R = 5r
Both balls are spherical.
The surface area of the cricket ball is given as:

The surface area of the football is given as:


Therefore, the ratio of their surface areas is:
A : a

= 100 : 4
25 : 1