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schepotkina [342]
1 year ago
11

1.3 puzzle time why did the fraction jump into boiling water

Mathematics
1 answer:
Slav-nsk [51]1 year ago
3 0

Answer:

The fraction jumped into boiling water because it wanted to be reduced.

Step-by-step explanation:

This is a maths riddle about fractions. We often see fractions that we might feel could be reduced. So, if these kinds of fractions jumps into a boiling water, they get reduced. The riddle is rather funny though.

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Together, Katya and Mimi have 480 pennies in their piggy banks. After Katya lost ½ of her pennies and Mimi lost 2/3 of her penni
vesna_86 [32]

Answer:

288 pennies

Step-by-step explanation:

6 0
2 years ago
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a golfer needs to hit a ball a distance of 500 feet, but there is a 60-foot tall tree that is 100 feet in front of the point whe
jok3333 [9.3K]

We can create a parabola equation of the trajectory using the vertex form:

y = a (x – h)^2 + k

 

The center is at h and k, where h and k are the points at the maximum height so:

h = 250

k = 120

 

Therefore:

 y = a (x – 250)^2 + 120

 

At the initial point, x = 0, y = 0, so we can solve for a:

0 = a (0 – 250)^2 + 120

0 = a (62,500) + 120

a = -0.00192

 

So the whole equation is:

y = -0.00192 (x – 250)^2 + 120

 

So find for y when the golf ball is above the tree, x = 400:

y = -0.00192 (400 - 250)^2 + 120

y = 76.8 ft

 

So the ball cleared the tree by:

76.8 ft – 60 ft = 16.8 ft

 

 

Answer:

16.8 ft

8 0
2 years ago
Find the absolute value of 3.1+(-6.3)
Sliva [168]

Answer:

3.2

Step-by-step explanation:

First, evalue what's inside of the absolute value:

3.1 + (-6.3) = -3.2

Now, since absolute value means the distance from the number to 0, the absolute value of -3.2 is the negation of -3.2:

|-3.2| = 3.2

7 0
1 year ago
In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
7nadin3 [17]

Correct answer is: distance from D to AB is 6cm

Solution:-

Let us assume E is the altitude drawn from D to AB.

Given that m∠ACB=120° and ABC is isosceles which means

m∠ABC=m∠BAC = \frac{180-120}{2}=30

And AC= BC

Let AC=BC=x

Then from ΔACD , cos(∠ACD) = \frac{DC}{AC} =\frac{4}{x}

Since DCB is a straight line m∠ACD+m∠ACB =180

                                              m∠ACD = 180-m∠ACB = 60

Hence cos(60)=\frac{4}{x}

          x=\frac{4}{cos60}= 8

Now let us consider ΔBDE, sin(∠DBE) = \frac{DE}{DB} =\frac{DE}{DA+AB} = \frac{DE}{4+8}

DE = 12sin(30) = 6cm

7 0
2 years ago
In isosceles △ABC (AC = BC) with base angle 30° CD is a median. How long is the leg of △ABC, if sum of the perimeters of △ACD an
SIZIF [17.4K]

Note necessary facts about isosceles triangle ABC:

  • The median CD drawn to the base AB is also an altitude to tha base in isosceles triangle (CD⊥AB). This gives you that triangles ACD and BCD are congruent right triangles with hypotenuses AC and BC, respectively.
  • The legs AB and BC of isosceles triangle ABC are congruent, AC=BC.
  • Angles at the base AB are congruent, m∠A=m∠B=30°.

1. Consider right triangle ACD. The adjacent angle to the leg AD is 30°, so the hypotenuse AC is twice the opposite leg CD to the angle A.

AC=2CD.

2. Consider right triangle BCD. The adjacent angle to the leg BD is 30°, so the hypotenuse BC is twice the opposite leg CD to the angle B.

BC=2CD.

3. Find the perimeters of triangles ACD, BCD and ABC:

P_{ACD}=AC+CD+AD=2CD+CD+AD=3CD+AD;

P_{BCD}=BC+CD+BD=2CD+CD+AD=3CD+AD;

P_{ABC}=AC+BC+AB=2CD+2CD+AD+BD=4CD+2AD.

4.  If sum of the perimeters of △ACD and △BCD is 20 cm more than the perimeter of △ABC, then

P_{ACD}+P_{BCD}=P_{ABC}+20,\\ \\3CD+AD+3CD+AD=4CD+2AD+20,\\ \\6CD+2AD=4CD+2AD+20,\\ \\2CD=20.

5. Since AC=BC=2CD, then the legs AC and BC of isosceles triangles have length 20 cm.

Answer: 20 cm.

8 0
2 years ago
Read 2 more answers
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