He needs to score between 3.5 points more at the next game to make it to the all tournament team at the minimum. good luck with the question!!
You have two 30-60-90 triangles, ADC and BDC.
The ratio of the lengths of the sides of a 30-60-90 triangle is
short leg : long leg : hypotenuse
1 : sqrt(3) : 2
Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC
First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30
Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10
AB = AC - BC = 30 - 10 = 20
as far as I can tell, is just a matter of going around the circle many or infinite times around.
so 6,31° is the first point, the next point will be one-go-around, 6, 31+360 => 6, 391°
then the next will be 6, 391+360 => 6, 751° and so on.
so we can say is (6, 31° ±360°n), n ∈ ℤ.
Answer: <span>w = [ y + 1] / [a + 2]
Solution step by step:
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1) given <span>formula: y-aw=2w-1
2) transpose aw and - 1
2w + aw = y + 1
3) common factor w:
w (a + 2) = y + 1
4) divide both sides by (a + 2):
w = [ y + 1] / [a + 2]
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