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marta [7]
2 years ago
5

Patrick made two loaves of cinnamon swirl bread to give his neighbors for the holidays. He added 2 ounces of cinnamon to 16 ounc

es of bread dough to make the first loaf, which he gave to the couple across the street. He added 3 ounces of cinnamon to 24 ounces of bread dough to make the second loaf, which he gave to the family next door. Which loaf had a stronger cinnamon flavor?
Mathematics
1 answer:
IgorC [24]2 years ago
7 0

Answer: neither

Step-by-step explanation: for every ounce of cinnamon, it’s 8 ounces of bread dough. the ratio is 1:8, which means for 24 ounces of bread dough there’s 3 ounces of cinnamon.

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STatiana [176]
3,2,-5,-7 that is the order it should be in
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A 4-ounce cup of coffee costs $8.00. How much would a 3-ounce cup of cofee codt?
romanna [79]
To solve this, we must first find out the cost-per-ounce of a cup of coffee. Assuming that the rates are flat, then we can just divide the 8-dollar-cost by the 4-ounce cup that it buys.

8 / 4 = 2

The cost-per-ounce of a cup of coffee is $2.
Now, we just have to multiply the cost-per-ounce by the amount of coffee we want to find out the cost of.

2 * 3 = 6

With all else constant, a 3-ounce cup of coffee would cost $6.
Hope that helped! =)
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A guy wire is used to support flagpoles in windy areas. These wires are anchored in the ground to provide constant stability. Yo
r-ruslan [8.4K]

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Length of wire,x=cos 31.13=x/15

15cos31.13

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8 0
2 years ago
A customer at Logan’s Plants pays $20.00 for a bush and $11.50 per pack of flowers. The table shows the total cost to purchase o
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6 0
2 years ago
In a class of 30 students (x+10) study algebra, (10x+3) study statistics, 4 study both algebra and statistics. 2x study only alg
Vladimir [108]

Answer:

1. The Venn diagrams are attached

2. When the statistics students number = 10·x + 3, we have;

The number of students that study

a. Algebra = 128/11

b. Statistic = 213/11

When the statistics students number = 2·x + 3, we have;

The number of students that study

a. Algebra = 16

b. Statistic = 15

Step-by-step explanation:

The parameters given are;

Total number of students = 30

Number of students that study algebra n(A) = x + 10

Number of students that study statistics n(B) = 10·x + 3

Number of student that study both algebra and statistics n(A∩B) = 4

Number of student that study only algebra n(A\B) = 2·x

Number of students that study neither algebra or statistics n(A∪B)' = 3

Therefore;

The number of students that study either algebra or statistics = n(A∪B)

From set theory we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 10·x + 3 - 4 = 27

11·x+13 = 27 + 4 = 31

11·x = 18

x = 18/11

The number of students that study

a. Algebra

n(A) = 18/11 + 10 = 128/11

b. Statistic

n(B) = 213/11

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 128/11 - 4 = 84/11

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 213/11 - 4 = 169/11

However, assuming n(B) = (2·x + 3), we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 2·x + 3 - 4 = 27

2·x+3 + x + 10= 27 + 4 = 31

3·x = 18

x = 6

Therefore, the number of students that study

a. Algebra

n(A) = 16

b. Statistics

n(B) = 15

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 16 - 4 = 12

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 15 - 4 = 11

The Venn diagrams can be presented as follows;

6 0
2 years ago
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