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tamaranim1 [39]
2 years ago
14

Jeremy is a 17-year-old junior in high school and just started his first job. He wants to open a savings account. Which of these

will he need to bring to the local bank branch in order to start an account?
Mathematics
2 answers:
garik1379 [7]2 years ago
6 0
There are no choices lol
Aleksandr [31]2 years ago
3 0

A. A letter from his school

B. A letter from his parents

C. An adult cosigner because he is under 18

D. An adult cosigner because he is still a student


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Consider the diagram and the paragraph proof below. Given: Right △ABC as shown where CD is an altitude of the triangle Prove: a2
gladu [14]
The answer is B.

This is because since f + e = c,
then a² + b² = c(f + e)
a² + b² = c(c)
a² + b² = c²

This is the correct answer 
5 0
2 years ago
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Tricia saved money, but the amount she saved didn't meet both her emergency needs and savings for her goal. Which of these would
Hoochie [10]
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Consider the initial value problem: 2ty′=8y, y(−1)=1. Find the value of the constant C and the exponent r so that y=Ctr is the s
VikaD [51]

The correct question is:

Consider the initial value problem

2ty' = 8y, y(-1) = 1

(a) Find the value of the constant C and the exponent r such that y = Ct^r is the solution of this initial value problem.

b) Determine the largest interval of the form a < t < b on which the existence and uniqueness theorem for first order linear differential equations guarantees the existence of a unique solution.

c) What is the actual interval of existence for the solution obtained in part (a) ?

Step-by-step explanation:

Given the differential equation

2ty' = 8y

a) We need to find the value of the constant C and r, such that y = Ct^r is a solution to the differential equation together with the initial condition y(-1) = 1.

Since Ct^r is a solution to the initial value problem, it means that y = Ct^r satisfies the said problem. That is

2tdy/dt - 8y = 0

Implies

2td(Ct^r)/dt - 8(Ct^r) = 0

2tCrt^(r - 1) - 8Ct^r = 0

2Crt^r - 8Ct^r = 0

(2r - 8)Ct^r = 0

But Ct^r ≠ 0

=> 2r - 8 = 0 or r = 8/2 = 4

Now, we have r = 4, which implies that

y = Ct^4

Applying the initial condition y(-1) = 1, we put y = 1 when t = -1

1 = C(-1)^4

C = 1

So, y = t^4

b) Let y = F(x,y)................(1)

Suppose F(x, y) is continuous on some region, R = {(x, y) : x_0 − δ < x < x_0 + δ, y_0 −ę < y < y_0 + ę} containing the point (x_0, y_0). Then there exists a number δ1 (possibly smaller than δ) so that a solution y = f(x) to (1) is defined for x_0 − δ1 < x < x_0 + δ1.

Now, suppose that both F(x, y)

and ∂F/∂y are continuous functions defined on a region R. Then there exists a number δ2

(possibly smaller than δ1) so that the solution y = f(x) to (1) is

the unique solution to (1) for x_0 − δ2 < x < x_0 + δ2.

c) Firstly, we write the differential equation 2ty' = 8y in standard form as

y' - (4/t)y = 0

0 is always continuous, but -4/t has discontinuity at t = 0

So, the solution to differential equation exists everywhere, apart from t = 0.

The interval is (-infinity, 0) n (0, infinity)

n - means intersection.

7 0
1 year ago
1. Sarah has an average of 92.5 for her 3 science tests. What does she need to make on the 4th test to get a 94% average. 
zheka24 [161]
1) set up a problem
you know you want to get an avg of 94 but how do you do avg in the first place. you add up the numbers then divde by the total number of numbers used lol

so \frac{92.5+x}{2}=94
92.5 is the avg number for the last 3 tests
"x" is the 4th test score which we want to find out
"2" is the total number of numbers being added together

so now lets get x to one side

92.5+ x=94*2 (multiply 2 to both sides)
92.5+x=188
x=188-92.5  (subtract 92.5 from both sides)
x= 95.5  this is the score she need to make to avg 94%

2) you can draw a tree diagram. for example Flower1 branches off into 3 diff greens and then each of those greens branch off into 2 for with or with babies breath.

or you can simple multiply 4*3*2. you can do this because all choices are included with no restriction

your total number of options is 24
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2 years ago
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