The city council hired three college interns to measure public support for a large parks and recreation initiative in their city
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Step-by-step explanation:
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<u>Answer:</u>
The value of variable "m" in the equation 803 divided by 73 = m is equal to 11.
<u>Solution:</u>
Need to find the variable in the given equation 803 divided by 73 = m
That means need to solve below expression to determine value of variable m.
So let’s solve left hand side to get the value of m.
For sake of simplicity let’s do factorization of numerator and denominator and remove the common terms in numerator and denominator.
Hence value of variable m is equal to 11.
Answer: (a) 4
(b) 5
(c) 14
(d)
Class interval Class mark
30 - 35
35 - 40
40 - 45
45 - 50
50 - 55
Step-by-step explanation:
The data of 40 persons is given as :
Weights (in kg) Frequency
30 - 35 6
35 - 40 13
40 - 45 14
45 - 50 4
50 - 55 3
(a)
<em>Lower limit is the lowest number in a class interval .</em>
So, is the lower limit of fourth-class interval (45 - 50) is 4.
(b)
<em>Class size = Upper limit - lower limit </em>
So, Class size of first class interval = 35-30=5
Thus , class size of each interval is 5. [ class size remains same]
(c)
Highest frequency in table = 14 which is corresponding to 40 - 45 .
Thus , 40 - 45 is the class interval has the highest frequency.
(d)
<em>Class mark is the mid value of each class interval.</em>
<em>Class interval = </em>
Class interval Class mark
30 - 35
35 - 40
40 - 45
45 - 50
50 - 55