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Rainbow [258]
1 year ago
13

When the equation a – bx = cx + d is solved for x, the result is x = StartFraction a minus d Over b plus c EndFraction..

Mathematics
2 answers:
kiruha [24]1 year ago
8 0

Answer:

x = -12/14 is the required solution for the given expression.

Step-by-step explanation:

Here, the given expression is:

5 – 6 x  = 8 x + 17

Now, here solving the expression for the value of x, we get:

5 – 6 x  = 8 x + 17

⇒ 5 -  17   = 8 x +  6 x

⇒- 12  = 14 x

or, x  = -12 / 14

Hence, x = -12/14 is the required solution for the given expression.

ExtremeBDS [4]1 year ago
5 0

Answer: -6/7

Step-by-step explanation:

5 - 6x = 8x + 17

<u>-5                 -5</u>  <= subtract 5 from both sides

-6 x = 8x + 12

<u>-8x    -8x  </u><= subtract -8x from both sides to isolate the variable

<u>-14x</u> =<u> 12</u>

-14     -14 <= divide by -14 to factor out and isolate x

-12/14 can be simplified to  -6/7

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The following table shows the number of hours some teachers in two schools expect students to spend on homework each week: Schoo
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Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

IQR=Q_3-Q_1=16-6.5=9.5

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

IQR=Q_3-Q_1=15.5-8=7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

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2 years ago
. Cara is playing a game. For each dart she can toss onto a board, she
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1 year ago
Emma was about to finish grocery shopping when she noticed that cans of soup were on sale. Her total bill for groceries would be
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Answer:

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Step-by-step explanation:

Total bill

= cost of cans(number of cans) +cost of other groceries

Let the cost of other groceries be G, and the cost of cans be X.

Given that number of cans= C,

Total bill= XC +G

If 2 cans were purchased,

2X+G= 89.61 -----(1)

If 5 cans were purchased,

5X +G= 94.98 -----(2)

(2) -(1):

(5X +G) -(2X +G)= 94.98 -89.61

5X +G -2x -G= 5.37

3X= 5.37

X= 5.37 ÷3 <em>(</em><em>÷</em><em>3</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

X= 1.79

Subst. X= 1.79 into (1):

2(1.79) +G= 89.61

3.58 +G= 89.61

G= 89.61 -3.58 <em>(</em><em>-3.58</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

G= 86.03 <em>(</em><em>simplify</em><em>)</em>

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= 1.79C +86.03

Thus, the function is B(C)= 1.79C +86.03.

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