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2 years ago

What is the length of the y-component of the vector plotted below?

Mathematics

1 answer:

Inessa05 [86]2 years ago

7 0

Answer:

Option A.

Step-by-step explanation:

The vector shown in the figure has components on the x axis and on the y axis.

If each small box on the draw represents a unit, it can be seen that the vector has a component of<u> length equal to 1 on the positive y-axis </u>and a length equal to 4 on the positive x-axis.

Look at the attached image

The sum of these two components results in the vector shown in the figure. Therefore the correct option is option A.

The length is equal to 1

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According to a 2014 research study of national student engagement in the U.S., the average college student spends 17 hours per w

Nadusha1986 [10]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 17

For the alternative hypothesis,

µ < 17

This is a left tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 80,

Degrees of freedom, df = n - 1 = 80 - 1 = 79

t = (x - µ)/(s/√n)

Where

x = sample mean = 15.6

µ = population mean = 17

s = samples standard deviation = 4.5

t = (15.6 - 17)/(4.5/√80) = - 2.78

We would determine the p value using the t test calculator. It becomes

p = 0.0034

Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.

The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.

4 0

2 years ago

Quadrilateral ABCD ABCD is similar to quadrilateral EFGH EFGH. The lengths of the three longest sides in quadrilateral ABCD ABCD

Kay [80]

Sketch the two quadrilaterals and label them as shown in the figure below.

Let x = length of the 4th side of ABCD.

Because ABCD ~ EFGH, therefore
x/5 = 14/6

That is,
x = (5/6)*14 = 11.67 ft

Answer: D. 11.7 ft

5 0

2 years ago

Find the equation of the line passing through the point (2,−4) that is parallel to the line y=3x+2

Naily [24]

Hey there! :)

Line passes through (2, -4) & parallel to y = 3x+ 2

Let's start off by identifying what our slope is. In the slope-intercept form y=mx+b, we know that "m" is our slope. "M" is simply a place mat so if we look at our given line, the "m" value is 3. Therefore, our slope is 3.

We should also note that we're looking for a line that's parallel to the given one. This means that our new line has the same slope as our given line. Therefore, our slope for our new line will be 3.

Now, we use point-slope form ( y-y₁=m(x-x₁) ) to complete our task of finding a line that passes through (2, -4) with a slope of 3.

y-y₁=m(x-x₁)

Let's start by plugging in 3 for m (our slope), 2 for x1 and -4 for y1.

y - (-4) = 3(x - 2)

Simplify.

y + 4 = 3x - 6

Simplify by subtracting 4 from both sides.

y = 3x - 10

~Hope I helped!~

8 0

2 years ago

What is the correlation coefficient of the linear fit of the data shown below, to the nearest hundredth?

sweet-ann [11.9K]

Not to sure but I think c

5 0

2 years ago

Read 2 more answers

In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th

ehidna [41]

Question:

In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th birthday, 25% married by their 20th birthday, and 76% married by their 30th birthday. Based on these data, what is the probability that in a family with two daughters, the first and second daughter will be married by the following ages? (Enter your answers to four decimal places.) (a) 18 years of age (b) 20 years of age (c) 30 years of age

Answer:

A.) 0.0064

B.) 0.0625

C.) 0.5776

Step-by-step explanation:

Given the following :

Married by 18th birthday = 8% = 0.08

Married by 20th birthday = 25% = 0.25

Married by 30th birthday = 76% = 0.76

In a family with two(2) daughters :

P(First daughter will be married by 18) = 0.08

P(second daughter will be married by 18) = 0.08

P(1st and 2nd married by 18) = (0.08×0.08) = 0.0064

B.)

P(First daughter will be married by 20) = 0.25

P(second daughter will be married by 20) = 0.25

P(1st and 2nd married by 20) = (0.25×0.25) = 0.0625

C.)

P(First daughter will be married by 30) = 0.76

P(second daughter will be married by 30) = 0.76

P(1st and 2nd married by 30) = (0.76×0.76) = 0.5776

6 0

1 year ago