Answer:
A cross section parallel to the base is a square measuring 4 cm by 4 cm.
A cross section perpendicular to the base through the midpoints of opposite sides is a square measuring 4 cm by 4 cm.
A cross section that passes through the entire bottom front edge and the entire top back edge is a rectangle measuring 4 cm by greater than 4 cm.
Step-by-step explanation:
Cross sections parallel and Perpendicular to the base are squares 4 × 4
The diagonal cross section will be a rectangle with base 4 and height
sqrt(4² + 4²) = 4sqrt(2) > 4
She has to buy both binders and notebooks. So, you have to take into account that she has to have both. The closest you can get to $20 while still getting notebooks, is to buy 4 binders. 4 times 4 equals 16. So, she can get 4 binders and 2 notebooks, because then, 2 times 2 equals 4 and 16 plus 4 equals 20.
Answer:
Ethan and Tenaya ate more than half of their pizza.
Sam and Suzy ate less than half of their pizza.
Step-by-step explanation:
We have been given that each of the four friends ordered individual pizzas. They ate some part of the pizzas and we have to find who ate more than half of their pizza? Less than half?
Suzy ate 3/8 of her pizza. It means she ate 0.375 of her pizza which is less than half.
Ethan ate 3/5 of his pizza. It means he ate 0.6 of his pizza which is greater than half.
Tenaya ate 4/6 of her pizza. It means she ate 0.67 of his pizza which is greater than half.
Sam ate 1/3 oh his pizza. It means he ate 0.3 of his pizza which is less than half.
Hence, we can conclude that
Ethan and Tenaya ate more than half of their pizza.
Sam and Suzy ate less than half of their pizza.
Answer:
78% probability that a randomly selected online customer does not live within 50 miles of a physical store.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, we have that:
Total outcomes:
100 customers
Desired outcomes:
A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.
Using this estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical store?

78% probability that a randomly selected online customer does not live within 50 miles of a physical store.