Answer:
∴Third side = 12 units
Step-by-step explanation:
In ΔCAB, the measure of segment AB is 8 units and the measure of segment AC is 5 units.
The sum of two sides of a triangle always grater than third side.
Therefore,
(5+8)=13 units
third side<13
∴Third side = 12 units
Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) = 
= 0.25
P(X ≥ 15) = 
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50
Let x = the length of the rectangle
Let w= the width
Two sections are required, hence 2w of fence required
2x+3w=500
this can be written as:
3w=1500-2x
w=(1500-2x)/3
Area=x*w
replacing w with our expression:
A=x(1500-2x)/3
A=(500x-2x^2)/3
This is a quadratic equation, if we find the axis of symmetry we will know what value of x gives maximum area:
Axis of symmetry: x=-b/2a
From our equation we get:
a=-2/3; b=1500/3
thus
x=(1500/3)/(-(-2/3))
x=750
thus the maximum area will be given by length of 750
ANSWER:
C. Place the compass on point A. Open the compass to a point between point P and point B.
EXPLANATION:
A perpendicular is a line that would be at a right angle to line BA.
The next step is to chose a radius that is greater than PB or PA so as to construct the bisector. And this can be done by placing the compass on point A, and open the compass to a point between point P and point B.
Use this radius to draw an arc above and below the line, and repeat the same using B as the center with the same radius. This would form two intersecting arcs above and below line BA. Join the point of intersection of the arcs by a straight line through P. This is the bisector of line BA through point P.
If the perimeter is 13y-5, then it should be equal to all of these sides added together. So, let’s add all of the sides we already know up:
5y-4 + y + 3y+1 = 9y-3.
Now set this equal to the perimeter we already know:
9y-3 = 13y-5. Subtract 9y from both sides.
-3 = 4y-5. Add 3 to both sides.
4y-2.
Now we have the value of 4y-2. Since we know that the last two sides are completely the same, then we can divide this expression by 2.
Therefore, the remaining side is 2y-1.