Question

Keith tabulated the following values for time spent napping in minutes of six of his friends: 23, 35, 17, 30, 20, and 19. The standard deviation is 7.043 Keith reads that the mean nap is 22 minutes. The t-statistic for a two-sided test would be __________. Answer choices are rounded to the hundredths place. 1.39 or 1.43 or 2.88 or 0.70

Answer 1

Answer:

The  t-statistic is $t = 0.6956$

Step-by-step explanation:

From the question we are told that

     The population mean is  $\mu = 22 \ minutes$

       The standard deviation is  $s = 7.043$

       The  given data is  23, 35, 17, 30, 20, and 19.

Generally the sample mean is mathematically evaluated as

      $\= x = \frac{23+ 35+17+ 30+ 20+ 19 }{6}$

     $\= x =24$

The t-statistic is mathematically evaluated as

       $t = \frac{ \= x - \mu }{\frac{s}{ \sqrt{n} } }$

=>   $t = \frac{ 24 - 22 }{\frac{ 7.043}{ \sqrt{6} } }$

=>   $t = 0.6956$