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shepuryov [24]
2 years ago
7

Toyota advertises that their Toyota Highlander Hybrid provide 28 MPG. To test this, an experiment involving a sample of 20 Toyot

a Highlander Hybrid vehicles is conducted. In this experiment, for every vehicle, the MPG in the vehicle's computer while it was set at 60 miles per hour on cruise control is recorded. The sample mean MPG recorded is 28.8 miles per gallon with a standard deviation of 6.89 miles per gallon. Use this information to conduct the following hypothesis test at 0.01 level of significance:
Null hypothesis: The population mean MPG of Toyota Highlander Hybrid vehicles is equal to 28 miles per gallon.

Alternative hypothesis: The population mean MPG is Toyota Highlander Hybrid vehicles is not equal to 28 miles per gallon.

What is your conclusion from this test?

a. do not reject the null

b. accept the null

c. reject the null

d. none of these
Mathematics
1 answer:
klemol [59]2 years ago
5 0

Answer:

We accept the null hypothesis.    

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = 28.8 miles per gallon

Sample size, n = 120

Alpha, α = 0.01

Sample standard deviation, σ = 6.89 miles per gallon

First, we design the null and the alternate hypothesis

H_{0}: \mu = 28\text{ miles per gallon.}\\H_A: \mu \neq 28\text{ miles per gallon.}

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{28.8 - 28}{\frac{6.89}{\sqrt{19}} } = 0.5061

Now, t_{critical} \text{ at 0.01 level of significance, 19 degree of freedom } =\pm 2.8609 Since,            

-2.609 < t_{stat} < 2.8609

We fail to reject the null hypothesis and accept it.

We accept the null hypothesis and the population mean MPG of Toyota Highlander Hybrid vehicles is equal to 28 miles per gallon.

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\frac{4}{20} can be simplified to \frac{1}{5}, which means we need to work out \frac{1}{5} of 12.2

\frac{1}{5} is equivalent to 20%, which as a decimal is 0.2

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A test has a mean of 80 with a standard deviation of 4. Which of the following scores is within one standard deviation of the me
Bogdan [553]

Answer:

B

Step-by-step explanation:

Mathematically, we shall be using the z-score here

Z-score = (x-mean)/SD

From the question, mean = 80 and SD = 4

So we want to get the option in the question that has a z-score of 1 or below

Let’s look at 75

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For 77;

80 -77 = 3

This is less than the standard deviation of 4, meaning it is within 1 standard deviation of the mean

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In a school building, there are 8 exterior doors and 12 stairways to enter the second floor. Find a total number of ways to reac
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Think of it in groups.

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A certain shade of green paint is made from 5 parts yellow mixed with three parts blue if 2 cans of yellow are used how many can
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A campus deli serves 300 customers over its busy lunch period from 11:30 a.m. to 1:30 p.m. A quick count of the number of custom
Irina-Kira [14]

Complete question is;

A campus deli serves 300 customers over its busy lunch period from 11:30 am to 1:30 pm. A quick count of the number of customers waiting in line and being served by the sandwich makers shows that an average of 10 customers are in process at any point in time. What is the average amount of time that a customer spends in process?

Answer:

4 minutes

Step-by-step explanation:

For this question, we will apply Little's law which is is a theorem that determines the average number of items in a stationary queuing system, based on the average waiting time of an item within a system and the average number of items arriving at the system per unit of time.

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We are given;

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Thus, plugging in the relevant values, we get ;

We are told that an average of 10 customers are in process at any point in time.

Thus;

Average flow time = average inventory/flow rate = 10/2.5 = 4 minutes

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