Let S = number of small yogurts ($2 each).
Let M = number of medium yogurts ($3 each)
Let L = number of large yogurts ($5 each)
Total yogurts is 27, therefore
S + M + L = 27
Total revenue generated is $98, therefore
2S + 3M +5L = 98
There are five more large yogurts than small yogurts, therefore
L = S + 5, or
-S + L = 5
These three equations may be written as the matrix equation
[ 1 1 1 | |S| |27|
| 2 3 5 | |M| = |98|
| -1 0 1 | |L| | 5|
The determinant of the matrix is
D = 3 - (2+5) + 3 = -1.
Solve with Cramer's Rule to obtain
S = -[27*3) - (98-25) - 15]
= 7
M = -[(98-25) - 27(2+5) + (10+98)]
= 8
L = -[15 - (10+98) + 27(3)]
= 12
Answer: 7 small, 8 medium, 12 large yogurts.
Step 1
<u>Find the measure of angle x</u>
we know that
If ray NP bisects <MNQ
then
m<MNQ=m<PNM+m<PNQ ------> equation A
and
m<PNM=m<PNQ -------> equation B
we have that
m<MNQ=(8x+12)°
m<PNQ=78°
so
substitute in equation A
(8x+12)=78+78-------> 8x+12=156------> 8x=156-12
8x=144------> x=18°
Step 2
<u>Find the measure of angle y</u>
we have
m<PNM=(3y-9)°
m<PNM=78°
so
3y-9=78------> 3y=87------> y=29°
therefore
<u>the answer is</u>
the measure of x is 18° and the measure of y is 29°
It would be thirty six seconds over one-fourth mile= 144 miles per hour
Answer:
Step-by-step explanation:
Confidence interval is written in the form, sample mean ± margin of error
The sample mean is an estimator for the population mean. The confidence level is used to express how confident we are that the population mean is within the calculated confidence interval. The lower limit of the given confidence interval is 2.619 hours/day while the upper limit of the confidence interval is 3.401 hours/day
Therefore, the INVALID interpretations of the 95% confidence interval are
A. About 95% of all Cal Poly students spend between 2.619 and 3.401 hours/day watching TV.
B. There is a 95% chance that, on average, Cal Poly students spend between 2.619 and 3.401 hours/day watching TV.
D. In the long run, 95% of the sample means will be between 2.619 and 3.401 hours.
E. None of the above.
