1 mile at 12 m/h is .2 m/min
1 mile at .2 m/min (1/.2) = 5 min So the first mile took 5 minutes
To find how fast the second mile was:
You know it was 1 mile and it took 10 minutes
1/10=.1 m/min which is 6 m/h
The average speed is 6+12/2=9 m/h
Hope that helps. Feel free to ask any questions.
Answer:
Inherently asymmetrical casual relationship.
Step-by-step explanation:
The dog owners are given free dog food samples which contain new vegetables. These samples are given to them by organizing booths at the dog events. The reaction of the dog owners is observed towards this new dog food. This an example of inherently asymmetrical relationship.
Answer:
5901
Step-by-step explanation:
The margin of error is the critical value times the standard error.
ME = CV × SE
For α = 0.05, the critical value is z = 1.96.
The standard error of a proportion is √(pq/n). Given p = 0.04, then q = 1−p = 0.96.
The margin of error is 0.5% or 0.005.
Plugging in:
0.005 = 1.96 √(0.04 × 0.96 / n)
n ≈ 5901
Answer:
To answer your question: Rewrite 81x2 as (9x)2.(9x)2−49Rewrite 49 as 72.(9x)2−72 Both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) where a=9x and b=7.(9x+7)(9x−7)
Let number of yellow marbles = x
Let number of red marbles = y
Let number of blue marbles = z
Given that Finley has 152 yellow, red, and blue marbles in a bag.
So we get equation:
x+y+z=152...(i)
"He has seven more red marbles than yellow marbles" means:
y=x+7...(ii)
"three times as many blue marbles as yellow marbles." means:
z=3x...(iii)
Now we just need to solve those equations to find the answer.
Plug (ii) and (iii) into (i)
x+(x+7)+(3x)=152
x+x+7+3x=152
Which looks similar to choice (B)
5x+7=152
5x=145
x=29
Hence final answer is choice B.
Required equation is
x+x+7+3x=152
Number of yellow marbles = 29
