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Ratling [72]
2 years ago
11

Marcus is selling lemonade in peanuts each cup of lemonade cost $0.75 in each bag of peanuts cost $0.35 on Saturday market so 5

more cups of lemonade then bags of peanuts here in $7.05 how many cups of lemonade did Marcus sell on Saturday
Mathematics
1 answer:
Fed [463]2 years ago
7 0
Let L represent the number of cups of lemonade that Marcus sold. Then his revenue can be described by ...
   0.75L + 0.35(L -5) = 7.05
   1.10L -1.75 = 7.05 . . . . . . . . . . eliminate parentheses
   1.10L = 8.80 . . . . . . . . . . . . . . .add 1.75
   L = 8 . . . . . . . . . . . . . . . . . . . . .divide by 1.10

Marcus sold 8 cups of lemonade on Saturday.
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If tammy takes 200 steps to travel 1/4 of a city block, how many steps will she take to travel 4 1/2 city blocks?
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For 1/4 city, he takes = 200 steps
for a city, it is = 200 * 4 = 800

Now, for 4 1/2 = 9/2 city, he would take = 800 * 9/2 = 3600

In short, Your Answer would be 3600 steps

Hope this helps!
8 0
2 years ago
What number is 10 times greater than 12,052
AlekseyPX

Answer:

120,520

Step-by-step explanation:

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1 year ago
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A solid machine part is to be manufactured as shown in the figure. The part is made by cutting a small cone off the top of a lar
Alexxx [7]

Answer:

The answer is 390 × pi.

Step-by-step explanation:

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= 1/3 x 3.14 x 9^2 x 15

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Small cone:

V = 1/3 x pi x r^2 x h

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The answer is 390 × pi.

4 0
2 years ago
If an object is projected upward with an initial velocity of 129 ft per sec, its height h after t seconds is h = -16^2+123t. Fin
elena-s [515]

This problem can be solved directly by neglecting the initial velocity given. All we have to do is to plug in t = 4 in the given equation. That is:

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Hunter-Best [27]

Answer:

<em>A) (-5,7)</em>

Step-by-step explanation:

<u>Functions and Relations</u>

A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).

By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

\boxed{A)\ (-5,7)}

8 0
2 years ago
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