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DENIUS [597]
2 years ago
7

The art museum is 8 1/2 miles from Alison's house. Alison has ridden her bike 2/3 of the way there so far. How far how she gone?

In fraction answer
Mathematics
2 answers:
ozzi2 years ago
8 0
Alison is 2/3 of the way to the museum, so the answer is about 2/3 of 9, or 6 miles.  Let's calculate it:

  2                              17 miles
---- * (8 1/2 miles) = --------------     She has ridden (17/3) miles, which is 5 2/3 
 3                                    3             miles.
MissTica2 years ago
4 0

Answer:

5\frac{2}{3} miles

Step-by-step explanation:

Distance between  art museum and Alison's house = 8\frac{1}{2} miles

                                                                                       = \frac{17}{2} miles

Alison has ridden  2/3 of the way

So, She traveled distance = \frac{2}{3} \times \frac{17}{2}

                                           = \frac{17}{3}

                                           = 5\frac{2}{3}

Hence she gone 5\frac{2}{3} miles

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Answer:

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Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

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\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Do, integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Substitute the value in 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Hence Cardiac output:F=0.055 L\s

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Step-by-step explanation:

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