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2 years ago

7

The art museum is 8 1/2 miles from Alison's house. Alison has ridden her bike 2/3 of the way there so far. How far how she gone?

In fraction answer

2 answers:

ozzi2 years ago

8 0

Alison is 2/3 of the way to the museum, so the answer is about 2/3 of 9, or 6 miles. Let's calculate it:

2 17 miles
---- * (8 1/2 miles) = -------------- She has ridden (17/3) miles, which is 5 2/3
3 3 miles.

MissTica2 years ago

4 0

Answer:

$5\frac{2}{3}$ miles

Step-by-step explanation:

Distance between art museum and Alison's house = $8\frac{1}{2} miles$

= $\frac{17}{2} miles$

Alison has ridden 2/3 of the way

So, She traveled distance = $\frac{2}{3} \times \frac{17}{2}$

= $\frac{17}{3}$

= $5\frac{2}{3}$

Hence she gone $5\frac{2}{3}$ miles

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Step-by-step explanation:

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2 years ago

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During a field trip, 60 students are put into equal-sized groups. Describe two ways to interpret 60÷5 60 ÷ 5 in this context. Fi

Afina-wow [57]

The second question:

Consider the division expression $7\frac{1}{2} / 2$ . Select all multiplication equations that correspond to this division expression.

$2 * ? = 7\frac{1}{2}$ $7\frac{1}{2} * ?= 2$ $? * 2 = 7\frac{1}{2}$

$2* 7\frac{1}{2} = ?$ $? * 7\frac{1}{2} = 2$

Answer:

1. See Explanation

2. $2 * ? = 7\frac{1}{2}$ and $? * 2 = 7\frac{1}{2}$

Step-by-step explanation:

Solving (a):

Given

$Students = 60$

$Group = Equal\ Sized$

Required

Interpret $\frac{60}{5}$ in 2 ways

<u>Interpretation 1:</u> Number of groups if there are 5 students in each

<u>Interpretation 2:</u> Number of students in each group if there are 5 groups

<u>Solving the quotient</u>

$Quotient = \frac{60}{5}$

$Quotient = 12$

<u>For Interpretation 1:</u>

The quotient means: 12 groups

<u>For Interpretation 2:</u>

The quotient means: 12 students

Solving (b):

Given

$7\frac{1}{2} / 2$

Required

Select all equivalent multiplication equations

Let ? be the quotient of t $7\frac{1}{2} / 2$

So, we have:

$7\frac{1}{2}/2 = ?$

Multiply through by 2

$2 * 7\frac{1}{2}/2 = ? * 2$

$7\frac{1}{2} = ? * 2$

Rewrite as:

$? * 2 = 7\frac{1}{2}$ --- This is 1 equivalent expression

Apply commutative law of addition:

$2 * ? = 7\frac{1}{2}$ --- This is another equivalent expression

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2 years ago

A sociologist wishes to see if it is true that for a certain group of professional women, the average age at which they have the

Vadim26 [7]

Answer:

$Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o$

Step-by-step explanation:

The explanation of given question is described below:

Here, the test of hypothesis states that

$H_o : Mean = 28.6$

$H_a : Mean\ which\ is\ not\ equals\ 28.6$

The test statistic is

$Z = \frac{(\bar X - Mean)}{\frac{Population\ standard\ deviation}{vn} }$

$Z = \frac{(30.06 - 28.6)}{\frac{4.18}{6} }$

= 2.1

According to the given data α = 0.05,

So, the major value is

$IZ(0.025)I = 1.96$

(refer to the standard normal table) .

Finally

$Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o$

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2 years ago

Here is a flower made up of yellow hexagons, red trapezoids, and green triangles. How many copies of this flower pattern could y

olganol [36]

Answer:

Part a) You could build 5 copies of the flower pattern

Part b) You would have 40 red trapezoids left over

Step-by-step explanation:

The complete question in the attached figure

Part a)

Let

x -----> the number of yellow hexagons

y ----> the number of red trapezoids

z ----> the number of green triangles

we know that

The flower pattern has the following ratios

$\frac{x}{y}=\frac{6}{2} ---->\frac{x}{y}=3 ----> \text {equation A}$

$\frac{x}{z}=\frac{6}{9} -->\frac{x}{z}=\frac{2}{3} --> \text {equation B}$

$\frac{y}{z}=\frac{2}{9} ------> \text {equation C}$

Find out how many copies of this flower pattern could you build if you had 30 yellow hexagons,50 red trapezoids, and 60 green triangles

1) For x=30

Divide 30 by 6 (remember that in one pattern there are 6 yellow hexagons)

$30/6=5\ copies$

Verify the quantity of y needed and the quantity of z needed

Find the value of y

$\frac{30}{y}=3 ---->y=30/3=10\\$

10 < 50 ----> is ok

Find the value of z

$\frac{30}{z}=\frac{2}{3} ---> z=30*3/2=45$

45<60 --->is ok

2) For y=50

Divide 50 by 2 (remember that in one pattern there are 2 red trapezoids)

$50/2=25\ copies$

Verify the quantity of x needed and the quantity of z needed

Find the value of x

$\frac{x}{50}=3 ---->x=50*3=150$

150 > 30 ----> is not ok

3) For z=60

Divide 60 by 9 (remember that in one pattern there are 9 green triangles)

60/9=6.7 copies

Round down

6 copies -----> 6(9)=54 green triangles

Verify the quantity of x needed and the quantity of y needed

Find the value of x

$\frac{x}{54}=\frac{2}{3} ---> z=54*2/3=36$

36> 30 --->is not ok

therefore

You could build 5 copies of the flower pattern

Part b)

we know that

x:y:z=6:2:9

If you build 5 copies

1) You would use 5*6=30 yellow hexagons and you would have 0 hexagons left over

2) You would use 5*2=10 red trapezoids and you would have (50-10=40) trapezoids left over

3) You would use 5*9=45 green triangles and you would have (60-45=15) triangles left over

therefore

You would have 40 red trapezoids left over

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1 year ago

Lieutenant Commander Data is planning to make his monthly (every 30 days) trek to Gamma Hydra City to pick up a supply of isolin

Nookie1986 [14]

Answer:

a

$N = 209 \ unites$

b

$N_{max} = 249$

Step-by-step explanation:

From the question we are told that

The daily demand is $d = 7/day$

The standard deviation is $\sigma = 3 /day$

The service probability is $s = 95\% = 0.95$

The number of chips in the inventory is $k = 40$

The number of days in his monthly is $T = 30 \ days$

The lead time is $L = 4$

Generally the number he should order (optimal order ) is mathematically represented as

$N = d(L + T)+(\sigma_{T + L} * z) -k$

Here $\sigma__{T+L }}$ is the monthly standard deviation which is mathematically evaluated as

$\sigma__{T + L}} = \sqrt{(T + L) * 1^2}$

=> $\sigma__{T + L}} = \sqrt{34}$

=> $\sigma__{T+L}} = 5.83$

Also z-value for the 95% service probability from the z-table is 1.96

So

$N = 7 * (30 +4 ) + (1.96 * 5.83) - 40$

=> $N = 209 \ unites$

For the maximum order quantity k = 0

So

$N_{max} = d(L + T)+(\sigma_{T + L} * z) -0$

=> $N_{max} = 7 * (30 +4 ) + (1.96 * 5.83) - 0$

=> $N_{max} = 249$

7 0

2 years ago