Answer:
0.32km
Step-by-step explanation:
The speed that a tsunami can travel is modeled by the equation s = 356 StartRoot d EndRoot , where S is the speed in kilometers per hour and d is the average depth of the water in kilometers.
This is written mathematically as:
S = 356√d
What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?
S = 200km/hr
Hence:
200km/hr = 356√d
Divide both sides by 356
200/356 = 356√d/356
√d = 200/356
Square both sides
(√d)² = (200/356)²
d =(0.5617977528)²
d = 0.3156167151km
Approximately = 0.32km
Answer: Expected value of the daily cost of operating the machine is 235.264.
Step-by-step explanation:
Since we have given that
E[x]= 0.96 repairs per day
And Var[x] = 0.96 repairs per day.

![E[c]=160+40E[x^2]\\\\E[c]=160+40(Var[x]+(E[x])^2)\\\\E[c]=160+40(0.96+0.96^2)\\\\E[c]=235.264](https://tex.z-dn.net/?f=E%5Bc%5D%3D160%2B40E%5Bx%5E2%5D%5C%5C%5C%5CE%5Bc%5D%3D160%2B40%28Var%5Bx%5D%2B%28E%5Bx%5D%29%5E2%29%5C%5C%5C%5CE%5Bc%5D%3D160%2B40%280.96%2B0.96%5E2%29%5C%5C%5C%5CE%5Bc%5D%3D235.264)
Hence, Expected value of the daily cost of operating the machine is 235.264.
Answer:
x = 9 5/11
Step-by-step explanation:
22x + 7 = 215
22x = 215-7
22x = 208
x = 208/22
x = 9 5/11
Answer:
0.514
Step-by-step Explantion:
Denominator = 500 = 2^2 * 5^3
257/500 = 257/2^2*5^3 = 2*257/2*2^2*5^3 = 514/2^3*5^3 = 514/(2*5)^3 = 514/10^3 = 0.514