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kvasek [131]
2 years ago
12

The product of a number,and 0.28 is 13.44. which equation matches this statement

Mathematics
2 answers:
n200080 [17]2 years ago
8 0

Answer:

Let the number be x

x × 0.28 = 13.44

x = 13.44/0.28

x = 48

8_murik_8 [283]2 years ago
7 0

Answer:

one day 2 babies were born in 1 hour home babie was 0.28LBS less heavier that the baby that was 13.44LBS whats the difference between the babies?

Step-by-step explanation:

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What is the slope of the line shown?<br> a -7/9 <br> b 9/7 <br> c 7/9 <br> d -9/7
max2010maxim [7]
Slope = y2 - y1/x2 - x1
6 - -3/1 - -6
=9/7
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All students are classified as either full-time or part-time. Kenneth conducted a survey in which he collected data on the perce
Crank

Answer:

A

Step-by-step explanation:

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2 years ago
The average heights of four samples taken from a population of students are shown in the table. Which of these is most likely cl
Ne4ueva [31]

Answer:

It would be D, 62

Step-by-step explanation:

The sample size for the group with the average height is the highest, being at 40 instead of 30, 20, or 10, and therefore has the most accurate average height.

7 0
2 years ago
Read 2 more answers
Please help. I am getting in trouble so please try to be correct...
vichka [17]

Answer: The answer is A 17in2

Step-by-step explanation:

In the question it states that the triangles are congruent (both the same).

  first I found the area of the top orange triangle.

the formula to find the area of a triangle is \frac{1}{2} bh (base times Height).

so I did  \frac{1}{2} 3.23* 5.12  which gave me 8.27.

Since the triangles are congruent (the same) they would both have the same area along with base and height. so I multiplied 8.27 by 2 (because there are two triangles) and got 16.54 which rounds up to 17.

the question also stated to find the APPROXIMATE area (close to the actual, but not completely accurate or exact.)

7 0
1 year ago
Of 1,050 randomly selected adults, 360 identified themselves as manual laborers, 280 identified themselves as non-manual wage ea
garik1379 [7]

Answer:

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

Step-by-step explanation:

We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.

We have to calculate a 95% confidence interval for the proportion.

The sample proportion is p=0.26.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.26*0.74}{160}}\\\\\\ \sigma_p=\sqrt{0.0012}=0.0347

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.96 \cdot 0.0347=0.068

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.26-0.068=0.192\\\\UL=p+z \cdot \sigma_p = 0.26+0.068=0.328

The 95% confidence interval for the population proportion is (0.192, 0.328).

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

3 0
2 years ago
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