Answer:
B
Step-by-step explanation:
The order does not matter. The intersection point will be the same regardless of the order the arcs are drawn in.
Answer:
$15
Step-by-step explanation:
Let Frank be f
Deandra be d and
Charlie be c
f = 3d ......(i)
c=$20+f.....(ii)
c=$65........(iii)
Equate (ii) and (iii)
$20+f = $65
f = $45.......(iv)
Equate (i) and (iv)
3d = $45
d = $15
Deandra has $15.
For the house A we have:
f (x) = 124270 (1.04) ^ x
Evaluating for 7, 8, 9 and 10 we have:
f (7) = 124270 (1.04) ^ 7 = 163530.8422
f (8) = 124270 (1.04) ^ 8 = 170072.0759
f (9) = 124270 (1.04) ^ 9 = 176874.9589
f (10) = 124270 (1.04) ^ 10 = 183949.9573
For house B we have:
f (x) = 114270 (1.05) ^ x
Evaluating for 7, 8, 9 and 10 we have:
f (7) = 114270 (1.05) ^ 7 = 160789.3653
f (8) = 114270 (1.05) ^ 8 = 168828.8336
f (9) = 114270 (1.05) ^ 9 = 177270.2752
f (10) = 114270 (1.05) ^ 10 = 186133.789
We observe that for years 7 and 8 the value of house A is greater than the value of house B.
Answer:
7 and 8
Create the sum of the given polynomial terms.
f(x,y) = 3x² - 2x²y + 2xy² + 4y² + xy² - y² + 2x²y
= 3x² + 3xy² + 3y²
Test the given terms to see if they belong in f(x,y).
3: NO
3x²: YES
3y²: YES
3xy²: YES
4x²: NO
Answer:
The terms in the sum of the given polynomials are 3x², 3y², and 3xy².
Answer:
MArginal productivity: 
We can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.
Step-by-step explanation:
The marginal productivy is the instant rate of change in the result for an increase in one unit of a factor.
In this case, the productivity is the time he last in the 100-yard. The factor is the amount of yards he train per week.
The marginal productivity can be expressed as:
where dt is the variation in time and dL is the variation in training yards.
We can not derive the function because it is not defined, but we can approximate with the last two points given:
Then we can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.
This is an approximation that is valid in the interval of 60,000 to 70,000 yards of training.
