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KatRina [158]
2 years ago
12

A package of self-sticking notepads contains 6 yellow, 6 blue, 6 green, and 6 pink notepads. An experiment consists of randomly

selecting one of the notepads and recording its color. Find the probability that a green notepad is selected given that it is either blue or green.
Mathematics
1 answer:
Rufina [12.5K]2 years ago
7 0

Answer:

0.50

Step-by-step explanation:

Given that a package of self-sticking notepads contains 6 yellow, 6 blue, 6 green, and 6 pink notepads. An experiment consists of randomly selecting one of the notepads and recording its color

The probability that a green notepad is selected given that it is either blue or green is to be found out

Let A = event that selected notepad is green or blue

B = selected notepad is green

The probability that a green notepad is selected given that it is either blue or green is to be found out

= P(B/A)

=P(AB)/P(A)

=Prob (green)/P(green or blue)

= \frac{\frac{Green}{Total} }{\frac{Green+Blue}{Total} } \\=\frac{6/24}{12/24} \\=0.50

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Start with the solution
x=-25
use the reverse of what they asked
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we use multiplication and subtract

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minus 10 from both sides
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stiks02 [169]

Answer:

See explanation

Step-by-step explanation:

A. Solution set is in the attachment (dark green shading in the middle)

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50 points decreased by 26% is how many points?
vampirchik [111]
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6 0
2 years ago
John painted his most famous work,in his country,in 1930 on composition board with perimeter 103.48 in. If the rectangular paint
Alexxandr [17]

Answer:

Width =22.955 in

length =28.785 in

Step-by-step explanation:

let width=x

painting is 5.83 in taller than it is wide

length =x+5.83

Perimeter of rectangle =2 (length+width)

Perimeter of painting =103.48

2(x+x+5.83)=103.48\\2x+5.83=51.74\\2x+51.74-5.83\\2x=45.91\\x=\frac{45}{2} \\x=22.955

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5 0
2 years ago
According to a report in USAToday, more and more parents are helping their young adult children get homes. Suppose eight persons
Inga [223]

Answer:

a)  95% confidence interval for the population proportion of all young adults in Kentucky who received help from their parents.

( 0.0761 , 0.3239)

b) Margin of error  =  0.1264.

Step-by-step explanation:

<u>Explanation</u>:-

Given '8' persons in a random sample of 40 young adults who recently purchased a home in Kentucky received help from their parents.

sample proportion of success 'p' = \frac{8}{40} = 0.2

q = 1=p

q = 1-0.2 = 0.8

a)

95% confidence interval for the population proportion of all young adults in Kentucky who received help from their parents.

(p-1.96\sqrt{\frac{pq}{n} } , p+1.96\sqrt{\frac{pq}{n} } )

(0.2-1.96\sqrt{\frac{0.2X0.8}{40} } , 0.2+1.96\sqrt{\frac{0.2X0.8}{40} } )

(0.2 - 0.1239,0.2+0.1239)

( 0.0761 , 0.3239)

b) the margin of error for a 95% confidence interval for the population proportion.

For the 95% confidence interval ∝= 0.05 and zₐ = 1.96≅2.

Margin of error = \frac{2\sqrt{pq} }{\sqrt{n} }

Margin of error = \frac{2\sqrt{0.2X0.8} }{\sqrt{40} }

Margin of error for a 95% confidence interval for the population proportion.

Margin of error  =  0.1264.

4 0
2 years ago
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