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NNADVOKAT [17]
1 year ago
8

If x is the midpoint of ZW, then ZX=XW

Mathematics
1 answer:
sasho [114]1 year ago
4 0

Answer:

True.

Step-by-step explanation:

By definition of a mid point, it is located in the middle of two connected points. This means that the split is equal on both sides.

IF X is the midpoint of ZW, then ZX = XW.

~

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Insurance will pay $250,000 and Ronaldo will pay $90,000

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50/250 means 50 is the maxi9$50,000 per person for body injury liability while 250 means $250,000 maximum for one accident for body injury liability claim.

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2 years ago
What percent of 2b is: 0.04b; 0.2b; 0.56b; 1.8b; 2.5b; 3b; By what percent are they each larger or smaller than 2b
Leviafan [203]
.04b is 2% of 2b because .04 multiplied by 100 is 4 then you divide by 2 which gets you 2.
.04/2=x/100
cross multiply and divide
it is 98% smaller than 2b.

.2b is 10% of 2b because .2 multiplied by 100 is 20 then you divide by 2 and get 10.
.2/2=x/100
it is 90% smaller than 2b.

.56b is 28% of 2b because .56 multiplied by 100 is 56 then divide by 2 and you get 28.
.56/2=x/100
it is 72% smaller than 2b.

1.8b is 90% of 2b because 1.8 multiplied by 100 is 180 then divide it by 2. you get 90.
1.8/2=x/100
it is 10% smaller than 2b.

2.5b is 125% of 2b because 2.5 multiplied by 100 Is 250 and 250 divided by 2 is 125.
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it is 25% larger than 2b

3b is 150% of 2b because 3 multiplied by 100 is 300 and 300 divided by 2 is 150.
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7 0
2 years ago
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Two processes are used to produce forgings used in an aircraft wing assembly. Of 200 forgings selected from process 1, 10 do not
tangare [24]

Answer:

a.

\bar p_1=0.05\\\bar p_2=0.067

b-Check illustration  below

c.(-0.0517,0.0177

Step-by-step explanation:

a.let p_1  \& p_2 denote processes 1 & 2.

For p_1: T1=10,n1=200

For p_2:T2=20,n2=300

Therefore

\bar p_1=\frac{t_1}{N_1}=\frac{10}{200}=0.05\\\bar p_2=\frac{t_2}{N_2}=\frac{20}{300}=0.067

b. To test for hypothesis:-

i.

H_0:p_1=p_2\\H_A=p_1\neq p_2\\\alpha=0.05

ii.For a two sample Proportion test

Z=\frac{\bar p_1-\bar p_2}{\sqrt(\bar p(1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}\\

iii. for \frac{\alpha}{2}=(-1.96,+1.96) (0.5 alpha IS 0.025),

reject H_o if|Z|>1.96

iv. Do not reject H_o. The noncomforting proportions are not significantly different as calculated below:

z=\frac{0.050-0.067}{\sqrt {(0.06\times0.94)\times \frac{1}{500}}}

z=-0.78

c.(1-\alpha).100\% for the p1-p2 is given as:

(\bar p_1-\bar p_2)\pm Z_0_._5_\alpha \times \sqrt   \frac{ \bar p_1(1-\bar p_1)}{n_1}+\frac{\bar p_2(1-\bar p_2)}{n_2}\\\\=(0.05-0.067)\pm 1.645  \times \sqrt \ \frac{0.05+0.95}{200}+\frac{0.067+0.933}{300}\\

=(-0.0517,+0.0177)

*CI contains o, which implies that proportions are NOT significantly different.

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C.

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