Question

A cylindrical cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift. A cylinder has a height of 20 centimeters and a diameter of 8 centimeters. What is the approximate volume of the tube? Round to the nearest whole cubic centimeter. 1,005 cm3 1,340 cm3 3,351 cm3 4,021 cm3

Answer 1

Answer:

B

Step-by-step explanation:

Answer 2

Answer:

4021 cm^3

Step-by-step explanation:

The volume of a cylinder can be found using the following formula.

$V=\pi r^2h$

where r is the radius and h is the height.

We know the cylinder has a height of 20 centimeters and a diameter of 8 centimeters.

h= 20 cm

d= 8 cm

Substitute these values into the formula.

$V=\pi (8 cm^2) * 20 cm$

First, evaluate the exponent.

8 cm^2= 8 cm * 8 cm= 64 cm

$V=\pi * 64 cm^2*20 cm$

Multiply 64 cm^2 and 20 cm

$V=\pi *1280 cm^3$

Multiply 1280 cm^3 and pi

$V=4021.2386 cm^3$

Round to the nearest cubic centimeter. The 2 in the tenth place tells us to leave the number as is.

$V= 4,021 cm^3$

The volume is about 4,021 centimeters^3.