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2 years ago

13

Each type of cable has a prescribed bend radius , which is the radius of the maximum arc into which you can loop a cable without

impairing data transmission.

1 answer:

tiny-mole [99]2 years ago

7 0

The question is asking whether it is true or false so my answer is true.

You might be interested in

You purchased an $85,000 home, and the property taxes were $1530. If they make improvements and the house is now valued at $130,

drek231 [11]

Answer:

43470

Step-by-step explanation:

purchased of home =$85000

improvement of home =1530=

85000

+1530

=86530

the valued of home =130000=

130000

-86530=

43470

7 0

1 year ago

If sin(x) = 1/3 and sec(y) = 25/24 , where x and y lie between 0 and π/2, evaluate the expression using trigonometric identities

Dominik [7]

<span>sin(x-y) = (24-14*sqrt(2))/75 Write down what you know sin(x) = 1/3 sec(y) = 25/24 cos(y) = 1/sec(y) = 24/25 cos(x) = sqrt(1-sin(x)^2) = sqrt(1-1/9) = sqrt(8/9) = 2*sqrt(2)/3 sin(y) = sqrt(1-cos(y)^2) = sqrt(1-576/625) = sqrt(49/625) = 7/25 We now know the sin and cos of both x and y. Now to get the sin of x-y. sin(x-y) = sin(x)cos(y) - cos(x)sin(y) Substitute the known values for sin and cos of x and y, then evaluate and simplify sin(x-y) = (1/3)(24/25) - (2*sqrt(2)/3)(7/25) sin(x-y) = 24/75 - 14*sqrt(2)/75 sin(x-y) = (24-14*sqrt(2))/75</span>

5 0

2 years ago

Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A

MAVERICK [17]

Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
= -2cos4A*sin3A + 2cos4A*sinA
= 2cos4A(sinA - sin3A)
= 2cos4A*2cos(2A)sin(-A)
= -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
= 2cos4A*cos3A - 2cos4A*cosA
= 2cos4A(cos3A - cosA)
= 2cos4A*(-2)sin2A*sinA
= -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
= cos2A/sin2A
= cot2A

This verifies the identity.

4 0

2 years ago

Which graph shows the solution to the system of linear inequalities? x – 4y < 4 y < x + 1 Image for option 1 Image for opt

slava [35]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$x-4y$ ----> inequality A

solve for y

$-4y$

$4y>x-4$

$y> (x/4)-1$

The solution of the inequality A is the shaded area above the dashed line

The slope of the dashed line is positive

The y-intercept is the point $(0,-1)$

The x-intercept is the point $(4,0)$

$y< x+1$ ----> inequality B

The solution of the inequality B is the shaded area below the dashed line

The slope of the dashed line is positive

The y-intercept is the point $(0,1)$

The x-intercept is the point $(-1,0)$

Using a graphing tool

The solution of the system of inequalities in the attached figure

7 0

2 years ago

In a study in Scotland (as reported by Devlin 2009), researchers left a total of 320 wallets around Edinburgh, as though the wal

Ann [662]

Answer:

a) The observed proportion of wallets that were returned

p = 0.45625

b) <em> 95% of confidence intervals for Population proportion</em>

<em> 0.40168 , 0.51082)</em>

<em>c) The lower bound of the 95% confidence interval = 0.40168</em>

<em>d) The upper bound of the 95% confidence interval = 0.51082</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

a)

Given data the researchers left a total of 320 wallets around Edinburgh, as though the wallets were lost. Each contained contact information including an address. Of the wallets, 146 were returned by the people who found them

Given sample size 'n' = 320

Given data 'x ' = 146

<em>Sample proportion </em>

$p = \frac{x}{n}$

$p = \frac{x}{n} = \frac{146}{320} = 0.45625$

<u><em>Step(ii)</em></u>:-

b)<em> </em><u><em>95% of confidence intervals for Population proportion</em></u>

Level of significance = 95% or 0.05%

$Z_{\frac{\alpha }{2} } = Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96$

<em>95% of confidence intervals for Population proportion are determined by</em>

<em></em> $(p - Z_{0.025} \frac{\sqrt{p(1-p)} }{\sqrt{n} } , p + Z_{0.025} \frac{\sqrt{p(1-p)} }{\sqrt{n} })$ <em></em>

<em></em> $(0.45625 - 1.96\frac{\sqrt{0.45625(1-0.45625)} }{\sqrt{320} } , 0.45625 + 1.96\frac{\sqrt{0.45625(1-0.45625)} }{\sqrt{320} })$ <em></em>

<em>(0.45625 - 0.05457 , 0.45625 + 0.05457)</em>

<em>( 0.40168 , 0.51082) </em>

<em>c) The lower bound of the 95% confidence interval = 0.40168</em>

<em>d) The upper bound of the 95% confidence interval = 0.51082</em>

7 0

2 years ago