Find the limits of integration ly, uy, lx, ux, lz, uz (some of which will involve variables x,y,z) so that ∫uyly∫uzlz∫uxlxdxdzdy
represents the volume of the region in the first octant that is inside the paraboloid y=x2+9z2 and between the planes y=5 and y=10.
1 answer:
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Answer:
The measure of angle HBC is m∠HBC=61°
Step-by-step explanation:
In this problem we have that
The line BH bisects angle EBC,
see the attached figure to better understand the problem
then
m∠EBC=m∠EBH+m∠HBC
m∠EBH=m∠HBC
so
m∠EBC=2(m∠EBH)
substitute the given values and solve for a
<em>Find the measure of angle EBH</em>
m∠EBH=(4(4)+45)=61°
Remember that
m∠EBH=m∠HBC
therefore
The measure of angle HBC is m∠HBC=61°
Answer:
The perimeter of the trapezoid is
Step-by-step explanation:
we know that
The perimeter of the trapezoid is the sum of its four side lengths
so
In this problem
the formula to calculate the distance between two points is equal to
we have
step 1
Find the distance QR
substitute the values in the formula
step 2
Find the distance RS
substitute the values in the formula
step 3
Find the distance ST
substitute the values in the formula
step 4
Find the distance QT
substitute the values in the formula
step 5
Find the perimeter
Answer:
∅1=15°,∅2=75°,∅3=105°,∅4=165°,∅5=195°,∅6=255°,∅7=285°,
∅8=345°
Step-by-step explanation:
Data
r = 8 sin(2θ), r = 4 and r=4
iqualiting; 8.sin(2∅)=4; sin(2∅)=1/2, 2∅=asin(1/2), 2∅=30°, ∅=15°
according the graph 2, the cut points are:
I quadrant:
0+15° = 15°
90°-15°=75°
II quadrant:
90°+15°=105°
180°-15°=165°
III quadrant:
180°+15°=195°
270°-15°=255°
IV quadrant:
270°+15°=285°
360°-15°=345°
No intersection whit the pole (0)
