All categories

2 years ago

2. Which situation does have a final value of 0?

Mathematics

1 answer:

professor190 [17]2 years ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

It costs $5.15 to rent a kayak for 1 hour at a local state park. The price per hour stays the same for up to 5 hours of rental.

iren [92.7K]

5.15 x 5 = 25.75

25.75 + 3.75 = 29.5

So your answer is $29.50

Hope it helps! :D

6 0

2 years ago

How do you write 4540 million in standard form?

vovangra [49]

For this case what we should do is take into account the following conversion:
$million = 10 ^ 6
$
We then have the following number:
$4540 million
$
Applying the given conversion we have:
$4540 * 10 ^ 6
$
By doing the corresponding calculation we have that the standard form is given by:
$4540 * 10 ^ 6 = 4,540,000,000
$
Answer:
4540 million in standard form is:
$4,540,000,000$

8 0

2 years ago

Read 2 more answers

A hole is drilled in a sheet-metal component, and then a shaft is inserted through the hole. The shaft clearance is equal to dif

VashaNatasha [74]

Answer:

(A)

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

0 otherwise.

Step-by-step explanation:

(A)

We are looking for the probability that the random variable X is greater than 0.8.

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

For any $x$ you are looking for the probability $P(X \geq x)$ which is

$P(X \geq x) = \int\limits_{-\infty}^{x} 1.25(1-t^4) dt = \int\limits_{0}^{x} 1.25(1-t^4) dt = 1.25x - 0.25x^2$

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

0 otherwise.

5 0

2 years ago

The equation that represents the canned goods order is 24x + 64y = 384, where x = number of minutes spent producing fruit cans,

Sedaia [141]

I hope this helps you

3 0

2 years ago

Read 2 more answers

Jack and jill exercise in a 25.0-m-long swimming pool. jack swims nine lengths of the pool in 2 minutes and 34.5 seconds, while

grin007 [14]

Jack swims a distance of 9*25.0m=225.0 meters is 2 min and 34.5 seconds.

2 min and 34.5 seconds are 2*60sec +34.5 sec= 154.5 s

Jill covers 10*25.0m = 250 m in 154.5 s.

$\displaystyle{ Average\ Speed= \frac{Distance\ traveled}{Time \ of \ travel}\\\\$

$\displaystyle{ Average \ Velocity = \frac{Displacement}{time}$

thus,

the speed of Jack is : 225.0 meters /154.5 s =(225/154.5) m/s = 1.46 m/s

the speed of Jill is : 250.0 meters /154.5 s =(250/154.5) m/s = 1.62 m/s

Assuming Jack and Jill depart from point 0 towards the positive direction,

each even number of lengths, means Displacement = 0, and each odd number of lengths means Displacement = 25 m

So, average Velocity of Jill is 0,

average velocity of Jack is 25/ 154.5 = 0.16 m/s

Answer:

Average Speed of Jack : 1.46 m/s

Average Speed of Jill : 1.62 m/s

Average Velocity of Jack : 0

Average Velocity of Jill : 0.16 m/s

5 0

2 years ago