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Triss [41]
2 years ago
7

What is the value of x in the linear inequality? -3(4x-8.2) < -11.98x + 14 3/4

Mathematics
1 answer:
Dmitrij [34]2 years ago
8 0

-3(4x-8.2) < -11.98x + 14 3/4

Expand by using distributive property

-12x + 24.6 < -11.98x + 14.75

Subtract 24.6 from both sides

-12x < -11.98x - 9.85

Add both sides by -11.98x

-0.02x < - 9.85

Divide both sides by -0.02 (sign will be flipped)

x > 492.5

Hope it helps.

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11. The probability that a dessert sold at a certain cafe contains chocolate is 75%. The probability that a dessert containing c
raketka [301]
probability that a dessert sold at a certain cafe contains chocolate is 86%.

The probability that a dessert containing chocolate also contains nuts is 30%.

Find the probability that a dessert chosen at random contains nuts given that it contains chocolate

P(nuts given chocolate) = .30/.86 = .349 or 34
6 0
2 years ago
A hair salon in Cambridge, Massachusetts, reports that on seven randomly selected weekdays, the number of customers who visited
morpeh [17]

Answer:

a: 28 < µ < 34

Step-by-step explanation:

We need the mean, var, and standard deviation for the data set.  See first attached photo for calculations for these...

We get a mean of 222/7 = 31.7143

and a sample standard deviation of: 4.3079

We can now construct our confidence interval.  See the second attached photo for the construction steps.

They want a 90% confidence interval.  Our sample size is 7, so since n < 30, we will use a t-score.  Look up the value under the 10% area in 2 tails column, and degree of freedom is 6 (degree of freedom is always 1 less than sample size for confidence intervals when n < 30)

The t-value is: 1.943

We rounded down to the nearest person in the interval because we don't want to over estimate.  It said 28.55, so more than 28 but not quite 29, so if we use 29 as the lower limit, we could over estimate.  It's better to use 28 and underestimate a little when considering customer flow.

5 0
2 years ago
In professional basketball games during 2009-2010, when Kobe Bryant of the Los Angeles Lakers shot a pair of free throws, 8 time
ziro4ka [17]

Answer:

Is plausible that the successive throws are independent

Step-by-step explanation:

1) Table with info given

The observed values are given by the following table

__________________________________________________

First shot          Made          Second shot missed           Total

__________________________________________________

Made                  152                       33                                185

Missed                37                         8                                  45

__________________________________________________

Total                    189                       41                                230

2) Calculations and test

We are interested on check independence and for this we need to conduct a chi square test, the next step would be find the expected value:

Null hypothesis: Independence between two successive free throws

Alternative hypothesis: No Independence between two successive free throws

_____________________________________________________

First shot                    Made                                    Second shot missed

_____________________________________________________

Made                  189(185)/230=152.0217                41(185)/230=32.9783

Missed                189(45)/230=36.9783                  41(45)/230=8.0217

_____________________________________________________

On this case all the expected values are higher than 5 and the sample size 230 is enough to apply the chi squared test.

3) Calculate the chi square statistic

The statistic for this case is given by:

\chi_{cal}^2 =\sum \frac{(O_i -E_i)}{E_i}

Where O represent the observed values and E the expected values. Replacing the values that we got we have this

\chi_{cal}^2 =\frac{(152-152.0217)^2}{152.0217}+\frac{(33-32.9783)^2}{32.9783}+\frac{(37-36.9783)^2}{36.9783}+\frac{(8-8.0217)^2}{8.0217}=0.000003098+0.00001428+0.00001273+0.0.00005870=0.00008881

Now with the calculated value we can find the degrees of freedom

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Now we can calculate the p value

p_v =P(\chi^2 >0.00008881)=0.9925

On this case the pvalue is a very large value and that indicates that we can fail to reject the null hypothesis of independence. So is plausible that the successive throws are independent.

5 0
2 years ago
The two parts to a recursive formula are the starting term and the ____ used to find the next term.
DIA [1.3K]

Answer:

Recursive formulas give us two pieces of information:

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6 0
2 years ago
Read 2 more answers
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alexandr402 [8]

Answer:

$2.64

Step-by-step explanation:Get rid of the dollar sign and just subtract like normal.

 

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                                - 2.84

                                = 2.64

5 0
2 years ago
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