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Natali5045456 [20]
2 years ago
10

Astrid is in charge of building a new fleet of ships. Each ship requires 404040 tons of wood, and accommodates 300300300 sailors

. She receives a delivery of 444 tons of wood each day. The deliveries can continue for 100100100 days at most, afterwards the weather is too bad to allow them. Overall, she wants to build enough ships to accommodate at least 210021002100 sailors.
Mathematics
2 answers:
agasfer [191]2 years ago
5 0

Answer:

280 tons

Step-by-step explanation:

Khan Academy

prisoha [69]2 years ago
4 0

Answer:

10 Ships

Step-by-step explanation:

Source: Khan Academy

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Operations: Housekeeping Math Quiz
masha68 [24]

Answer:

Total time = 63 hours

Step-by-step explanation:

First, let us write out the information in the question:

rate at which rooms are cleaned = 20 mins/room

number of rooms = 175

one-fifth of the rooms take 40% longer to clean

Next, let us convert the extra time taken to clean the rooms from percentage to time.

40% of normal cleaning time = 40% of 20

= 40/100 × 20 = 0.4 × 20 = 8 minutes

∴ onw-fifth of the rooms take an extra 8 minutes = 28 minutes in total

Next, let us calculate how many of those rooms in the total 175 takes the extra cleaning time:

one-fifth of the rooms takes 28 minutes to clean means that:

1 in every 5 rooms out of the 175 rooms take 28 minutes to clean

∴ Number of rooms with extra cleaning time = 1/5 of 175

= 1/5 × 175 = 0.2 × 175 = 35

∴ 35 rooms take 28 minutes each to be cleaned.

Now let us calculate the total cleaning time:

if 35 rooms take the extra cleaning time, then the number of rooms that have the normal cleaning time is as follows:

175 - 35 = 140

Total time:

140 rooms taking 20 minutes per room = 140 × 20 = 2,800 munites

35 rooms taking 28 minutes per room = 35 × 28 = 980 minutes

Total cleaning time = 2800 + 980 = 3780 minutes

converting to hours (1 hour = 60 minutes)

∴ 3780 minutes = 3780 ÷ 60 = 63 hours (2 days and 15 hours)

8 0
2 years ago
Eighty-five more than the square of a number is the same as the square of the quantity that is $17$ less than the number. What i
Usimov [2.4K]
To solve that we first need to write it as an equation where x is the number:
85 + x^2 = (x-17)^2
85 + x^2 = x^2 - 34x + 289
Now organize the equation by gathering like terms in the same side lf the equation:
You can shift 85 to the other side by subtracting 85 from both sides of the equation:

85 - 85 + x^2 =x^2 34x +289 - 85
x^2 =x^2 + 34x +204

And shift x^2 to the other side by subtracting x^2 from both sides:
x^2 - x^2 =x^2 -x^2 + 34x +204
0 = 34x + 204

Shift 34x to the other side by subtracting 34x from sides
-34x = 34x - 34x + 204
-34x = 204

And now isolate x by dividing both sides of the equation by -34
-34/-34x = 204/-34
x = -6
Thats your awnser , the number is -6
I hope you understood my brief explanation...
5 0
2 years ago
A furniture store is having a sale on sofas and you're going to buy one. The advertisers know that buyers get to the store and t
KATRIN_1 [288]

Answer:

300

Step-by-step explanation:

5 0
2 years ago
Consider the midterm and final for a statistics class. Suppose 13% of students earned an A on the midterm. Of those students who
padilas [110]

Answer:

There is a 38.97% probability that this student earned an A on the midterm.

Step-by-step explanation:

The first step is that we have to find the percentage of students who got an A on the final exam.

Suppose 13% students earned an A on the midterm. Of those students who earned an A on the midterm, 47% received an A on the final, and 11% of the students who earned lower than an A on the midterm received an A on the final.

This means that

Of the 13% of students who earned an A on the midterm, 47% received an A on the final. Also, of the 87% who did not earn an A on the midterm, 11% received an A on the final.

So, the percentage of students who got an A on the final exam is

P_{A} = 0.13(0.47) + 0.87(0.11) = 0.1568

To find the probability that this student earned an A on the final test also earned on the midterm, we divide the percentage of students who got an A on both tests by the percentage of students who got an A on the final test.

The percentage of students who got an A on both tests is:

P_{AA} = 0.13(0.47) = 0.0611

The probability that the student also earned an A on the midterm is

P = \frac{P_{AA}}{P_{A}} = \frac{0.0611}{0.1568} = 0.3897

There is a 38.97% probability that this student earned an A on the midterm.

5 0
2 years ago
Judy’s brother Sam has a collection of 96, but what are the 10 way Sam can divide his comic books equal groups
Ierofanga [76]
He can divide by 2,3,4,6,8,12,16,24,32, and 48 but
8 0
2 years ago
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