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2 years ago

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Which represents the solution(s) of the graphed system of equations, y = x2 + x – 2 and y = 2x – 2? (–2, 0) and (0, 1) (0, –2) a

nd (1, 0) (–2, 0) and (1, 0) (0, –2) and (0, 1) Mark this and return

2 answers:

MA_775_DIABLO [31]2 years ago

5 0

Answer:

<h2>(0, -2) (1, 0)</h2>

Step-by-step explanation:

I got it right on the test... Have a great day :)

Luda [366]2 years ago

3 0

ANSWER

$(0,-2), (1,0)$

EXPLANATION

The first equation is

$y = {x}^{2} + x - 2$

The second equation is

$y = 2x - 2$

We equate both equations to get,

${x}^{2} + x - 2 = 2x - 2$

${x}^{2} + x - 2x - 2 + 2 = 0$

Simplify

${x}^{2} - x = 0$

Factor

$x(x - 1) = 0$

Either

$x = 0$

Or

$x - 1 = 0$

$x = 1$

Put x=0 or x=1 into the second equation to get,

$y = 2(0) - 2 = - 2$

Or

$y = 2(1) - 2 = 0$

Therefore the solutions are;

$(0,-2), (1,0)$

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Answer:

See the graph attached

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Explanation:

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Range: all real numbers (- ∞ , ∞)

x-intercept:

log ( -5.6x + 1.3) = 0 ⇒ -5.6x + 1.3 = 1 ⇒x = 0.3/5.6 ≈ 0.054

y-intercept:

x = 0 ⇒ log (0 + 1.3) = log (1.3) ≈ 0.11

Pick some other values and build a table:

x log (-5.6x + 1.3)

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You can see such graph on the picture attached: it is the red curve.

2) Graphing the equation 2 is easier because it is a line: y = - 1 - x

slope, m = - 1 (the coeficient of x)

y - intercept, b = - 1 (the constant term)

x - intercept: y = 0 = - 1 - x ⇒ x = - 1

The graph is the blue line on the picture.

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<u><em>x₁ ≈ - 2.1</em></u>

<u><em>x₂ ≈ 0.2</em></u>

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