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n200080 [17]
1 year ago
8

A gardener wants to run a border around the outside of her garden. She plots it on a grid to plan how much she will need. The ga

rden is in the shape of a rectangle with vertices at (2, 5) (8, 5) (8, 3) and (2, 3). Find the total length of border needed.
Mathematics
1 answer:
levacccp [35]1 year ago
5 0
Distance between (2, 5) and (8, 5) = 8 - 2 = 6
Distance between (8, 5) and (8, 3) = 5 - 3 = 2
Distance between (8, 3) and (2, 3) = 8 - 2 = 6
Distance between (2, 3) and (2, 5) = 5 - 3= 2

Total length of border = 6 + 2 + 6 + 2 = 16


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A length is measured as 21cm correct to 2 significant figures. what is the upper bound for the length?​
Leno4ka [110]

the upper bound for the length is  21.5  cm .

<u>Step-by-step explanation:</u>

Lower and Upper Bounds

  • The lower bound is the smallest value that will round up to the approximate value.
  • The upper bound is the smallest value that will round up to the next approximate value.

Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.

Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:

As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :

⇒ 21.5  cm

21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is  21.5  cm .

7 0
2 years ago
In circle A shown, BC || DE , mBC=58° and mDE=142°. Determine the measure of ZCFE . Show how you arrived at your answer.
AysviL [449]

Answer:

< CFE = 40°

Step-by-step explanation:

To better understand the solution, see attachment for the diagram.

Given:

BC parallel to DE

Measure of Arc BD = 58°

Measure of Arc DE = 142°

First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.

The line ST divides the arc BD and arc DE into half.

That is:

Arc SC = 1/2(arc BC) =1/2(58)

Arc SC = 29°

Arc TE = 1/2(arc DE) =1/2(142)

Arc TE = 71°

Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle

29° + Arc CE  + 71° = 180°

Arc CE + 100° = 180°

Arc CE = 180-100

Arc CE = 80°

Inscribed angle = 1/2(intercepted angle)

<CFE = 1/2(Arc CE )

<CFE = 1/2(80)

< CFE = 40°

5 0
1 year ago
In the diagram, P1P2 and Q1Q2are the perpendicular bisectors of AB¯¯¯¯¯ and BC¯¯¯¯¯, respectively. A1A2 and B1B2 are the angle b
4vir4ik [10]
We have to choose the correct answer for the center of the circumscribed circle of a triangle. The center of the circumscribed circle of a triangle is where the perpendicular bisectors of a triangle intersects. In this case P1P2 and Q1Q2 are perpendicular bisectors of sides AB and BC, respectively and they intersect at point P. S is the point where the angle bisectors intersect ( it is the center of the inscribed circle ). Answer: <span>P.</span>
7 0
1 year ago
A trader paid 1500 for 6 drinking cups. one of the cups got broken. he sold the remaining five, making a profit of 10percent cal
tankabanditka [31]

Answer:

Cost price of each cup = 1500/6 = 250

Selling price of each cup = 1650/5 = 330

Step-by-step explanation:

Cost price of cups = 1500

Profit = 10%

Selling price of cups = ?

Profit and loss percentage are calculated based on cost price and the formula to calculate profit is mentioned as under:

Profit percentage (%) = Profit x 100/Cost price

10 = Profit x 100/1500

⇒ Profit = 10 x 1500/100

⇒ Profit = 150

The formula for finding selling price is mentioned as under:

Selling Price = Profit + Cost Price.

Selling Price = 150 + 1500

⇒ Selling Price = 1650.

Since one of the six cups was broken that means the seller earned profit based on only 5 cups, it implies that selling price of each cup will be 1650/5 = 330.

6 0
1 year ago
Maggie has a ribbon 27 feet long.What is the length of the ribbon in yards?
finlep [7]
The ribbon would be 9 yards long
3 0
1 year ago
Read 2 more answers
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