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erastova [34]
2 years ago
8

If 16 of 200 apples were bad, what percent is that?

Mathematics
2 answers:
g100num [7]2 years ago
8 0
A. 8 percent
= 16/2
= 8%
blondinia [14]2 years ago
7 0

Answer:

:)

Step-by-step explanation:

It's 8 percent! Mark brainliest pls

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Sergio has p paintings in his art collection. He and other local painting collectors agreed to donate a total of 48
Tom [10]

Answer:

P - 4

Step-by-step explanation:

Sergio and the other painting collectors have decided to donate a total of 48 paintings all together.

We know that there are 12 collectors in total and they will each donate the same number of paintings.

48 paintings in total

12 collectors

48 / 12 = 4

We now know Sergio will donate 4 paintings from his collection of P paintings. Sergio will have P - 4 paintings left.

We do not know what "P" is equal to, so we cannot give an exact number for how many paintings he will have left. However, we know he will have 4 fewer paintings after donating.

3 0
2 years ago
How many quarts of peanut oil worth 19 cents per quart must be mixed with 100 quarts worth 25 cents per quart to produce a mixtu
ioda
<span>20 quarts of peanut oil worth 19 cents a quart are needed.</span>
3 0
2 years ago
Read 2 more answers
What is the logarithm of the equilibrium constant, log K, at 25°C of the voltaic cell constructed from the following two half-re
sashaice [31]

Answer:

4.0921 is the logarithm of the equilibrium constant.

Step-by-step explanation:

Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

Ag^+(aq) + e^-\rightarrow Ag(s); E° = 0.80 V

Iron having negative value of reduction potential .So ,that means that it will loose electron easily and get oxidized.Hence, will be at anode.

E^{o}_{cell}=Reduction potential of cathode - Reduction potential of anode

E^{o}_{cell}=E^{o}_c-E^{o}_a

=0.80 V-(-0.41 V)=1.21 V

Fe^{2+} (aq) + 2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

2Ag^+(aq) + 2e^-\rightarrow 2Ag(s); E° = 0.80 V

Net reaction: Fe(s)+2Ag^{+}\rightarrow Fe^{2+}+2Ag(s)

n = 2

To calculate equilibrium constant, we use the relation between Gibbs free energy, which is:

\Delta G^o=-nfE^o_{cell}

and,

\Delta G^o=-RT\ln K_{eq}

Equating these two equations, we get:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = number of electrons transferred = 2

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell = 1.21 V

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = 25^oC=[273+25]=298K

Putting values in above equation, we get:

2\times 96500\times 1.21 V=8.314\times 298\times \ln K_{eq}

\ln K_{eq}=9.3478

\log K_{eq}=\frac{9.3478}{2.303}=4.0921

4.0921 is the logarithm of the equilibrium constant.

7 0
2 years ago
Which ratio cannot form a proportion with 8/18<br> 1. 60/135<br> 2. 12/27<br> 3. 46/108<br> 4. 4/9
Gala2k [10]
Answer choice C can not form a proportion with 8/18.
7 0
2 years ago
There are 220 students in Year 7. 15% cycle to school. 60% are driven to school. The rest walk to school. (a) How many students
Paha777 [63]

Answer:

cycle=33 students, driven=132 students, walk=55 students

Step-by-step explanation:

<h2>solution</h2><h2>60+15+x=100 to get the remaining percentage</h2><h2>x=25</h2><h2>15÷100×220=33</h2><h2>60÷100×220=132</h2><h2>25÷100×220=55</h2>
7 0
2 years ago
Read 2 more answers
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