On Saturday, 4/4 of the amount of people attended. On Friday, 3/4 of the amount on Saturday attended. We have 7 parts (3 from Friday and 4 from Saturday).
840/7 = 120.
Thus, 360 people attend on Friday and 480 on Saturday.
We can tell from the data that there is a midpoint between the lowest and highest point of the clock, which is at a height of 9.5 feet.
Moreover, the lowest point occurs at 6 o clock, and the highest occurs at 12 o clock.
The amplitude of variation from the mid-point is 0.5 feet given by (10 - 9) / 2.
Finally, the time period for the equation is 12 hours. Thus, the answer is:
h = 0.5cos(πt/6) + 9.5, option B
First off, let's find the 1st term's value, and the 30th term's value,
The <em>correct answer</em> is:
P(x) = 13x² – 10x + 350; 1,102 fish
Explanation:
I plotted this data in a graphing calculator. The screenshot is attached. You can see the curve of the parabola in the graph. I then ran the quadratic regression; again, the screenshot is attached. It lists the values of a, b and c for the equation y = ax²+bx+c.