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1 year ago

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This box plot shows information about the marks scored in a test. 40 50 60 70 Points scored Nobody gained exactly 30, 48 or 70 m

arks. 120 students gained less than 70 marks. How many students gained more than 48 marks? 80 90 100 10 20 30

1 answer:

Sonbull [250]1 year ago

7 0

Answer:

80

Step-by-step explanation:

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In the diagram of circle A, what is the measure of ∠XYZ?<br><br> 35°<br> 70°<br> 75°<br> 140°

Mademuasel [1]

Answer: First Option is correct.

Step-by-step explanation:

Since we have given that

Measure of arc WZ = 175°

Measure of ∠XAZ = 105°

We need to find the measure of ∠XYZ.

As we know the angle subtended at the center is the average of the measure of arc intercepted by it angle and its vertical angles.

$\frac{175^\circ+\angle XYZ}{2}=105^\circ\\\\175^\circ+\angle XYZ=210^\circ\\\\\angle XYZ=210^\circ-175^\circ\\\\\angle XYZ=35^\circ$

Hence, the value of ∠XYZ is 35°.

Hence, First Option is correct.

3 0

1 year ago

Read 2 more answers

You roll a colored cube with one white side, two red sides, and three blue sides. What is the expected number of red sides you w

miskamm [114]

Hello!

This is an example of theoretical probability. If you rolled the die 1,000 times, you would probably roll red about 333 times. On average, this is 1/3, and with a die it is 2/6. As you can see, it will be rolled 2/6 of the time on average, so our answer is A) 2.

I hope this helps!

3 0

1 year ago

Read 2 more answers

An article in Fire Technology, 2014 (50.3) studied the effectiveness of sprinklers in fire control by the number of sprinklers t

gregori [183]

Answer:

probability that all of the sprinklers will operate correctly in a fire: 0.0282

Step-by-step explanation:

In order to solve this question we will use Binomial probability distribution because:

In the question it is given that the sprinklers activate correctly or not independently.
The number of outcomes are two i.e. sprinklers activate correctly or not.

A binomial distribution is a probability of a success or failures outcomes in an repeated multiple or n times.

Number of outcomes of this distributions are two.

The formula is:

b(x; n, P) = $C_{n,x}*p^{x} * (1 - p)^{n-x}$

b = binomial probability also represented as P(X=x)

x =no of successes

P = probability of a success on a single trial

n = no of trials

$C_{n,x}$ is calculated as:

$C_{n,x}$ = n! / x!(n – x)!

= 10! / 10!(10-10)!

= 1

According to given question:

probability of success i.e. p = 0.7 i.e. probability of a sprinkler to activate correctly.

number of trials i.e. n = 10 as number of sprinklers are 10

To find: probability that all of the sprinklers will operate correctly in a fire

X = 10 because we have to find the probability that "all" of the sprinklers will operate correctly and there are 10 sprinklers so all 10 of them

So putting these into the formula:

P(X=x) = $C_{n,x}*p^{x} * (1 - p)^{n-x}$

= C₁₀,₁₀ * 0.7¹⁰ * (1-0.7)¹⁰⁻¹⁰

= 1 * 0.0282 * (0.3) ⁰

= 1 * 0.0282 * 1

P(X=x) = 0.0282

5 0

1 year ago

Figures R, S, and T are all scaled copies of one another. Figure S is a scaled copy of R using a scale factor of 3. Figure T is

MakcuM [25]

<em><u>Answer:</u></em>

1/2

1/3

6

1/6

<em><u>Step-by-step explanation:</u></em>

When we are finding the opposite of a scale factor, the scale factor is always the reciprocal. E.g. From S to R, the scale factor is 3, so from R to S, the scale factor is 1/3 so:

1. From T to S, it's the reciprocal of the scale factor (2) so 1/2

2. From S to R, it's the reciprocal of the scale factor (3) so 1/3

3. From R to T, is the from a figure to a figure to a figure so we can multiply the two scale factors (2 and 3) to get 6

4. From T to R, that's the opposite of R to T, so it's the reciprocal of the scale factor from R to T (6) so 1/6

4 0

1 year ago

The crew of apollo 17 consisted of 2 pilots and a geologist. Suppose that nasa had actually trained 9 pilots and 4 geologists as

Troyanec [42]

They could have assembled total 336 different possible crews.

<em><u>Explanation</u></em>

Total number of trained pilots is 9 and geologists is 4.

The crew should be consisted of 2 pilots and 1 geologist. That means, <u>2 pilots are chosen from total 9 and 1 geologist is chosen from total 4</u>.

Number of ways for choosing 2 pilots from 9 $= ^9C_{3} =84$ and

Number of ways for choosing 1 geologist from 4 $=^4C_{1}= 4$

So, the total possible number of different crews they could have assembled $=84*4= 336$

8 0

2 years ago