The denominator of a certain fraction was 147 greater than its numerator. what was the denominator of this fraction, if after th
1 answer:
After reducing the fraction it becomes equal to 5/12. Let the common element which was cancelled out be x. So we can say the original fraction was 
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The denominator of the fraction is 147 greater than the numerator. We can write it as:
12x = 147 + 5x
12x - 5x = 147
7x = 147
x = 21
So, the numerator of the fraction was 5 x 21 = 105
Denominator of the fraction was 12 x 21 = 252
So our original fraction was
The denominator of the fraction is 147 greater than the numerator. We can write it as:
12x = 147 + 5x
12x - 5x = 147
7x = 147
x = 21
So, the numerator of the fraction was 5 x 21 = 105
Denominator of the fraction was 12 x 21 = 252
So our original fraction was
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Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer