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FromTheMoon [43]
1 year ago
15

Which expression is equivalent to 144 Superscript three-halves? 216 1,728 RootIndex 3 StartRoot 12 EndRoot RootIndex 3 StartRoot

72 EndRoot
Mathematics
2 answers:
Afina-wow [57]1 year ago
8 0

Question:

Which expression is equivalent to 144^(3/2)

Answer:

1728

Step-by-step explanation:

The options are not well presented. However, this is the solution to the question.

Given:

144^(3/2)

Required:

Find Equivalent.

We start my making use of the following law of logarithm.

A^(m/n) = (A^m)^1/n

So,

144^(3/2) = (144³)^½

Another law of indices is that

A^½ = √A

So,

144^(3/2) = (144³)^½ = √(144³)

144³ can be expanded as 144 * 144 * 144.

This gives

144^(3/2) = √(144 * 144 * 144)

The square root can then be splitted to

144^(3/2) = √144 * √144 * √144

144^(3/2) = 12 * 12 * 12

144^(3/2) = 1728.

Hence, the equivalent of 144^(3/2) is 1728

galina1969 [7]1 year ago
3 0

Answer:

B

Step-by-step explanation:

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the center of a circular sunflower with a diameter of 4 centimeters is (-2,1). Which equation represents the sunflower?
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The standard equation the circle is given by:
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2 years ago
Nick bought a pair of glasses for $200. He later saw the same glasses advertised for 20% less than what he originally paid. What
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2 years ago
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How many solutions does the equation sin(5x) = 1/2 have on the interval (0, 2PI]
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Answer:

Step-by-step explanation:

Given the equation

Sin(5x) = ½

5x = arcSin(½)

5x = 30°

Then,

The general formula for sin is

5θ = n180 + (-1)ⁿθ

Divide through by 5

θ = n•36 + (-1)ⁿ30/5

θ = 36n + (-1)ⁿ6

The range of the solution is

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First solution

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θ = 36n + (-1)ⁿθ

θ = 0×36 + (-1)^0×6

θ = 6°

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θ = 36n + (-1)ⁿ6

θ = 36-6

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When n = 2

θ = 36n + (-1)ⁿ6

θ = 36×2 + 6

θ = 78°

When n =3

θ = 36n + (-1)ⁿ6

θ = 36×3 - 6

θ = 102°

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θ = 36n + (-1)ⁿ6

θ = 36×4 + 6

θ = 150

When n =5

θ = 36n + (-1)ⁿ6

θ = 36×5 - 6

θ = 174°

When n = 6

θ = 36n+ (-1)ⁿ6

θ = 36×6 + 6

θ = 222°

When n = 7

θ = 36n + (-1)ⁿ6

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θ = 246°

When n =8

θ = 36n + (-1)ⁿ6

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When n =9

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When n =10

θ = 36n + (-1)ⁿ6

θ = 36×10 + 6

θ = 366°

When n = 10 is out of range of θ

Then, the solution is from n =0 to n=9

So the equation have 10 solutions in the range 0<θ<2π

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