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Temka [501]
2 years ago
6

Seven students cut 5 and three-fourths inches of thread from a spool for a school project. What number represents the change in

the amount of the thread on the spool?
Negative 40 and one-fourth inches
Negative 35 and three-fourths inches
Negative 29 and three-fourths inches
Negative 26 and one-fourth inches
Mathematics
2 answers:
Kitty [74]2 years ago
4 0

Answer:

3

Step-by-step explanation:

Reptile [31]2 years ago
4 0

Answer:

C.

Step-by-step explanation:

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WILL GIVE BRAINLIEST. Joanna saves nickels and quarters in a jar. If she saved five times as many nickels as quarters, and her c
vekshin1

Answer:

78 quarters

Step-by-step explanation:

I think because, I created an equation, 5x = 390 and solves to get 78

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2 years ago
How is (s-t)(s/t) equivalent to (s^2/t) -s
tigry1 [53]
(s-t)\cdot\dfrac{s}{t}=s\cdot\dfrac{s}{t}-t\cdot \dfrac{s}{t}=\dfrac{s^2}{t}-s
4 0
1 year ago
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Find the dependent and independent variable in r = 5s + 3.
Firdavs [7]

Answer:

The independent variable is s and the dependent variable is r

Step-by-step explanation:

r = 5s+3

The independent variable is s and the dependent variable is r

3 0
2 years ago
Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val
Cloud [144]

Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

A(t) = Pe^{rt}

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

$330 in an account in the year 1999

This means that P = 330

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

A(t) = Pe^{rt}

590 = 330e^{8r}

e^{8r} = \frac{590}{330}

e^{8r} = 1.79

Applying ln to both sides:

\ln{e^{8r}} = \ln{1.79}

8r = \ln{1.79}

r = \frac{\ln{1.79}}{8}

r = 0.0726

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

A(t) = 330e^{0.0726t}

A(10) = 330e^{0.0726*10} = 682

The value of the account in the year 2009 will be $682.

4 0
2 years ago
Compare partial products and regrouping how the methods are alike and different
shtirl [24]
<span>Partial products are different in regrouping in terms of how numbers are clustered from a set equation as a whole delivering it individual but naturally to all the numbers involved in the set. </span>
Regrouping is just like the commutative or associative property of numbers.
<span>Associative property of addition is used when you want to group addends. This is mainly used to cluster set of numbers or in this case, addends. How do you use the associative property when you break apart addends? Simple you group them using the open and closed parentheses or brackets. Take for an example 1 + 1 + 2 = 4. Using the associative property you can have either (1 + 1) + 2 = 4 or 1 + (1 + 2) = 4 clustered into place.  
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2 years ago
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