I assume you mean -x^3 + 4x + 3
so what you need is 4x + 3 > x^3
the only whole number it could be is 2 because 2x2x2 +3 > 2x2x2
Answer:
<h3>Negative (negative 20) = 20</h3>
Step-by-step explanation:
Given Shana temperature = -20°C
°If Pearls temperature is opposite that of Shana's then Pearls temparature = -(-20) = 20°C
Hence the correct way to represent "the opposite of Shana's temperature is equal to Pearl's
Opposite of shana = -(-20°C)
Pearls temperature = +20°C
Since Opposite of shana = Pearls temperature, hence -(-20°C) = 20°C
Answer:
The correct option is D.
Step-by-step explanation:
Domain is the set of all posible
The volume of a rectangular prism is

where,

Dimensions can not be negative. So, the width and volume are always positive.
From the graph it is noticed that
In interval
, width and volume is negative, so
interval is not the domain.
In interval (-5,0), width is negative, so (-5,0) interval is not the domain.
In interval (0,3), volume is negative, so (0,3) interval is not the domain.
In interval
, width and volume is negative, so
interval is not the domain.
Therefore the correct option is D.
Answer:
1. Take the Average of the distances the ball travelled each hit.
2. He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.
3. He should use Mean
4. He should use Median. It best measures skewed data
Step-by-step explanation:
THE FIRST PART.
Raul should take the average of the distances the ball travelled each hit.
This is done by summing the total distances the ball travelled each bounce, and then dividing the resulting value by the total number of times he hit the ball, which is 10.
THE SECOND PART
He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.
THE THIRD PART
He should take the mean of the distances of the ball that stayed infield.
This is the distance that occurred the most during the 9 bounces that stayed infield. The one that went outfield is makes it unfair to use any other measure of the center, taking the mean will give a value that is significantly below his efforts.
THE FOURTH PART
He should take the Median of the data, it is best for skewed data.
This is the middle value for all the distances he recorded.