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Svetach [21]
2 years ago
6

Suppose that 3% of the 2 million high school students who take the SAT each year receive special accommodations because of docum

ented disabilities. Consider a random sample of 20 students who have recently taken the test. (Round your probabilities to three decimal places.)(a) What is the probability that exactly 1 received a special accommodation?(b) What is the probability that at least 1 received a special accommodation?(c) What is the probability that at least 2 received a special accommodation?(d) What is the probability that the number among the 20 who received a special accommodation is within 2 standard deviations of the number you would expect to be accommodated? Hint: First, calculate ? and ?. Then calculate the probabilities for all integers between ? - 2? and ? + 2?.
Mathematics
1 answer:
icang [17]2 years ago
8 0

Answer:

See attachment for detailed answer.

Step-by-step explanation:

Download pdf
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Doris ran 2.5 kilometers, then sprinted 300 meters and finally walked 1 4 of the distance she sprinted. How many meters did she
mr Goodwill [35]

Answer:

She traveled a total of 2875 metres during practice.

Step-by-step explanation:

Doris ran 2.5 kilometres, then sprinted 300 meters and finally walked 1/4 of the distance she sprinted.

To find the total distance that she traveled, we simply add the distance that she ran, sprinted and walked.

We will convert all distances to metres.

She ran 2.5 kilometres:

1 km = 1000 m

2.5 km = 2.5 * 1000 = 2500 m

So, she ran 2500 m.

She sprinted 300 m.

Se walked 1/4 the distance that she sprinted:

1/4 * 300 = 75 m

She walked 75 m.

Therefore, the total distance she traveled is:

2500 + 300 + 75 = 2875 m

She traveled a total of 2875 metres during practice.

5 0
2 years ago
Samantha and Mia each left Julia’s house at the same time. Mia walked north at 7 kilometers per hour. Samantha ran west at 11 ki
Lena [83]
Mia walked 7km/h so after 1 hour, she is 7 km north of the house of Julia

Samantha walked 11km/h so after 1 hour, she is 11 km west of the house of Julia.

The points where Mia and Samantha are after 1 hour , and the house of Julia form a right triangle with sides 7 and 11 km. The distance between the girls, is the hypotenuse of his triangle.

 by the pythagorean theorem:

MS= \sqrt{ 7^{2} + 11^{2} }= \sqrt{49+121}= \sqrt{170}=  13 (km)


Answer: 13 km

3 0
2 years ago
Read 2 more answers
The student senate at a local university is about to hold elections. A representative from the women’s sports program and a repr
Amanda [17]

Answer: H0: p1 ≤ p2, Ha: p1 > p2

Step-by-step explanation:

According to the information obtained, we can say that the hypothesis that determines that the percentages of support votes are different between the two incumbent candidates is as follows

H0: p1 ≤ p2, Ha: p1> p2

where the null hypothesis represents the difference between proportions

6 0
2 years ago
Complete the following multiplication exercises.
olga2289 [7]
43x7=301
12x9=108
10x6=60
9x7=63
7x5=35
6x3=18
0x8=8
30x3=90
11x8=88
73x2=219
83x5=415
16x8=128
392x7=2,744
29x4=116
761x9=6,849
4,829x6=28,974
12x7=84
25,500x4=102,000
4 0
2 years ago
Read 2 more answers
World poultry production was 77.2 million tons in the year 2004 and increasing at a continuous rate of 1.6% per year. Assume tha
dezoksy [38]

Answer:

A) P(t)=77.2\cdot e^{0.016t}

B) 89.157 million tons.

C) In year 2017.

Step-by-step explanation:

We have been given that world poultry production was 77.2 million tons in the year 2004 and increasing at a continuous rate of 1.6% per year.

A). We know that a continuous growth function is in form y=a\cdot e^{kx}, where,

a = Initial value,

k = Growth rate in decimal form.

1.6\%=\frac{1.6}{100}=0.016

Upon substituting our given values, we will get:

P(t)=77.2\cdot e^{0.016t}

Therefore, our required function would be P(t)=77.2\cdot e^{0.016t}, where, P represents world poultry production, in million tons, as a function of the number of years, t, since 2004.

B) To find the world poultry production in the year 2013, we will substitute t=2013-2004=9 in above formula as:

P(9)=77.2\cdot e^{0.016(9)}

P(9)=77.2\cdot e^{0.144}

P(9)=77.2\cdot 1.1548841085249135

P(9)=89.1570531781\approx 89.157

Therefore, the world poultry production in the year 2013 would be 89.157 million tons.

C) To find the number of years it will take for world poultry production to be over 95 million tons, we will equate our function with 95 as:

95=77.2\cdot e^{0.016t}

Divide both sides by 77.2:

1.2305699481865285=e^{0.016t}

Take natural log of both sides:

\text{ln}(1.2305699481865285)=\text{ln}(e^{0.016t})

\text{ln}(1.2305699481865285)=0.016t\text{ln}(e)

0.20747743456981035=0.016t*1

Divide both sides by 0.016:

t=12.9673396606

t\approx 13

Therefore, 13 years after in 2017 world poultry production goes over 95 million tons.

4 0
2 years ago
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