E=13,000 and<span>E=1/50R(1650-R)</span>
<span>
</span>
<span />0.02R(1650-R)=13000
<span>(0.02R)(1650)-0.02R²=13000</span>
<span /><span>0.02R²-33R+13000=0</span>
<span>R2-1650R+650000=0</span>
<span>SOLVE W QUAD FORMULA
</span>
Answer:
The store paid 6.67 times the profit made on the jeans
Step-by-step explanation:
Let the amount the clothing store pay for Jean be X
Let the amount the clothing store sells Jean be Y = X ×1.15
The profit (P) made is the difference between amount the clothing store sells Jean and the amount paid for Jean = Y - X = 1.15X - X
Profit (P) = 0.15X
X = P/0.15 = 6.67P
Therefore, the store paid 6.67 times the profit made on the jeans
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
