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noname [10]
2 years ago
9

On January 1, 1970, Lois deposited $1950 into a savings account paying 6.6% interest, compounded semiannually. If she hasn't mad

e any additional deposits or withdrawals since then, and if the interest rate has stayed the same, in what year did her balance hit $3900, according to the rule of 72? A. 1979 B. 1981 C. 1982 D. 1980
Mathematics
2 answers:
Nutka1998 [239]2 years ago
7 0

Th correct answer is D. 1980

IgorLugansk [536]2 years ago
3 0

Answer:

D. 1980.      

Step-by-step explanation:

We have been given that on January 1, 1970, Lois deposited $1950 into a savings account paying 6.6% interest, compounded semiannually. We are asked to find the year in which Lois's balance hit $3900, according to the rule of 72.

The rule of 72 states the number of years it will take an investment to be double.

Since $3900 is twice the amount $1950, so we will divide 72 by our given interest rate to find the number of years it will take to double the given amount.

\text{Time it will take to double the given amount}=\frac{72}{6.6}

\text{Time it will take to double the given amount}=10.909090\approx 11

Since the amount will be double in 11th year, so 11th year after January 1, 1970 will be 1980.

Therefore, in year 1980 Lois amount will be double and option D is the correct choice.

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Dylan scored a total of 48 points in first 4 games of the basketball season. Which equation can be used to find g, the average n
belka [17]
G= 48/4???? that would make sense wouldn't it? because 48/4 would be the total number of points divided by the amount of games in which those points are scored. 

3 0
2 years ago
Read 2 more answers
A car travels at a constant speed of 65 miles per hour. The distance the car travels in Miles d, which is a function of time, t.
PolarNik [594]

Answer:

  t(d) = d/65

Step-by-step explanation:

To solve for t, divide by its coefficient:

  d = 65t

  d/65 = 65t/65 . . divide* by 65

  d/65 = t . . . . . . . simplify

Then you can write it in function form if you like:

  t(d) = d/65

_____

* Of course, the rules of equality say you must divide <em>both sides</em> of the equation by the same number.

4 0
2 years ago
Read 2 more answers
A repair bill for a car is $648.45. The parts cost $265.95. The labor cost is $85 per hour. Write and solve an equation to find
zysi [14]

Answer:

( t - p ) /  85x =  h

( t - 265.95 ) /  85x  = h

648.45 - 265.95 / 85x = 3.32h

h = 3.32

Therefore ( t - p ) /  85x =  3.32

Step-by-step explanation:

648.45 - 265.95

282.50 /85

= 3.32 hrs

Finding equation to find hours can be shown as

( t - p ) /  85x =  3.32

How we found equation to find total

Parts = 19 x 14 - 5/100 = 266- 0.05

648.45 - 265.95 = 282.5

282.5/85 = 3.323  near to 3,233529

Labour = 85x  = 17 (5 + x)

Equation = 17(5+ x) + 14(19) - 5/100 = 648.45 where x = 85

Equation = ( 85x x 3  1/3) + 265 - 19/20 = t

3 0
1 year ago
A principal of $2000 is placed in a savings account at 3% per annum compounded annually. How much is in the account after one ye
natita [175]

Answer:

Step-by-step explanation:

After one year

A=p(1+r/n)^nt

=2000(1+0.03/12)^12*1

=2000(1+0.0025)^12

=2000(1.0025)^12

=2000(1.0304)

=$2060.8

After two-years

A=p(1+r/n)^nt

=2060.8(1+0.03/12)^12*2

=2060.8(1+0.0025)^24

=2060.8(1.0025)^24

=2060.8(1.0618)

=$2188.157

After three years

A=p(1+r/n)^nt

=2188.157(1+0.03/12)^12*3

=2188.157(1+0.0025)^36

=2188.157(1.0025)^36

=2188.157(1.0941)

=$2394.063

8 0
2 years ago
A formula calls for 0.6 mL of a coloring solution. Using a 10-mL graduate calibrated from 2 to 10 mL in 1-mL units, how could yo
MrMuchimi

Answer:

let us add 2.4 mL of water in 0.6 ml of coloring solution

total volume of solution = 2.4 + 0.6 = 3 mL

therefore,

0.6 mL of coloring solution now includes = 2.4ml of water

or

1 mL of coloring solution includes = 4mL of water

Hence

measure 3 mL of coloring solution with water that is formed

therefore, this 3 mL will contain 0.6 mL of coloring solution

Step-by-step explanation:

Given:

formula calls for 0.6 mL of a coloring solution

10-mL graduate calibrated from 2 to 10 mL in 1-mL units

Now,

We want to use an aliquot technique to measure 0.6 ml of coloring solution.

Because the calibrated graduate is used to measure 2ml to 10ml with 1ml as unit measure

let us add 2.4 mL of water in 0.6 ml of coloring solution

total volume of solution = 2.4 + 0.6 = 3 mL

therefore,

0.6 mL of coloring solution now includes = 2.4ml of water

or

1 mL of coloring solution includes = 4mL of water

Hence

measure 3 mL of coloring solution with water that is formed

therefore, this 3 mL will contain 0.6 mL of coloring solution

3 0
2 years ago
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