For the first investment. A = P(1 + rt); where p = 9,720, r = 0.0316 and t = 1/12
A = 9720(1 + 0.0316/12) = 9720(1.0026) = $9,746
For the second investment,
A = 8140(1 + 0.0323 x 2) = 8140(1.0646) = $8,666
Total amount she had = $9,746 + $8,666 = $18,412
We need to assign a value for x to check the possible values of y.
1st inequality: y < -0.75x
X = - 1 ; y < -0.75(-1) ; y < 0.75 possible coordinate (-1,0.75) LOCATED AT THE 2ND QUADRANT
X = 0 ; y < -0.75(0) ; y < 0 possible coordinate (0,0) ORIGIN
X = 1 ; y < -0.75(1) ; y < -0.75 possible coordinate (1,-0.75) LOCATED AT THE 4TH QUADRANT
2nd inequality: y < 3x -2
X = -1 ; y < 3(-1) – 2 ; y < -5 possible coordinate (-1,-5) LOCATED AT THE 4TH QUADRANT
X = 0 ; y < 3(0) – 2 ; y < -2 possible coordinate (0,-2) LOCATED AT THE 4TH QUADRANT
X = 1 ; y < 3(1) – 2 ; y <<span> 1 possible coordinate (1,1) LOCATED AT THE 1ST QUADRANT
The actual solution to the system lies on the 4TH QUADRANT.
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2x+4x-4=2+4x
2x+4x-4x=2+4
2x=6
x=3
25-x=15-3x-10
3x-x= 15-10-25
2x= -20
x= -10
4x=2x+2x+5x-5x
2x+2x+5x-5x-4x
0 . no solution
Answer:
$6500
Step-by-step explanation:
Let the amount of money invested by Lian be $x
Interest rate = 5.2% per year
interest earned in first year will be 5.2% of amount of money invested by Lian .
(note: since in first year there will be no interest accrued on interest so interest for first year is simple interest )
interest earned in one year if money invested by Lian is $x
= 5.2% of $x (1)
But , it is given in one year she received interest of 338 dollars
so, 338 dollars must be equal to 5.2% of $x
equating $338 with 5.2% of $x , we have
5.2% of x = 338
=> (5.2/100) * x = 338
=>5.2 x = 338*100
=> x = 33800/5.2 = 6500.
Thus, amount of money Lian invested is $6500.