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Dmitry [639]
2 years ago
13

A jump rope held stationary by two children, one at each end, hangs in a shape that can be modeled by the equation h=0.01x^2-x+2

6, where h is the height (in inches) above the ground and x is the distance (in inches) along the ground measured from the horizontal position of one end. How close to the ground is the lowest part of the rope? A. 0.5 in. C. 1.25 in. B. 1 in. D. 2 in.

Mathematics
1 answer:
weqwewe [10]2 years ago
7 0

Answer:

  B.  1 in.

Step-by-step explanation:

For a quadratic of the form ...

  ax^2 +bx +c

The axis of symmetry is found at ...

  x = -b/(2a) = -(-1)/(2·0.01) = 50

The value of the function at x=50 is ...

  h = (0.01·50 -1)·50 +26 = -25+26

  h = 1

The lowest part of the rope is 1 inch above the ground.

_____

<em>Comment on the solution</em>

It is often easier to evaluate a quadratic or other polynomial if it is written in Horner's form:

  h = (ax +b)x +c

If you evaluate a polynomial using a synthetic division tableau, you will find the sequence of arithmetic operations to be identical.

___

A graphing calculator can make short work of a problem such as this.

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QUICK! 75 POINTS !!Select all that are part of the solution set of csc(x) &gt; 1 and over 0 ≤ x ≤ 2π.
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Answer:

\frac{\pi}{4}

\frac{5\pi}{6}

Step-by-step explanation:

The answer uses the unit circle and that sine and cosecant are reciprocals.

The first choice doesn't even fit the criteria that x is between 0 and 2\pi (inclusive of both endpoints) because of the x=\frac{-7\pi}{6}.

Let's check the second choice.

\csc(\frac{\pi}{4})=\frac{2}{\sqrt{2}} \text{ since } \sin(\frac{\pi}{4})=\frac{\sqrt{2}}{2}.

\csc(\frac{\pi}{4})>1 \text{ since } \frac{2}{\sqrt{2}}>1

\csc(\frac{\pi}{2})=1 \text{ since } \sin(\frac{\pi}{2})=1 which means \csc(\frac{\pi}{2})=1 which is not greater than 1.

So we can eliminate second choice.

Let's look at the third.

\csc(\frac{5\pi}{6})=2 \text{ since } \sin(\frac{5\pi}{6})=\frac{1}{2} which means \csc(\frac{5\pi}{6})>1.

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So we are eliminating 3rd choice now.

Let's look at the fourth choice.

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I was looking at the rows as if they were choices.

Let me break up my choices.

So we said x=-\frac{7\pi}{6} doesn't work because it is not included in the inequality 0\le x \le 2\pi.

How about x=0?  This leads to \csc(0) which doesn't exist because \sin(0)=0.

So neither of the first two choices on the first row.

Let's look at the second row again.

We said \frac{\pi}{4} worked but not \frac{\pi}{2}

Let's look at the choices on the third row.

We said \frac{5\pi}{6} worked but not x=\pi

Let's look at at the last choice.

We said it gave something less than 1 so this choice doesn't work.

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