Find what is common between 35 and 55....and that would be 5....so factor 5 out
35x + 55 =
5(7x + 11) <==
Given:
Taxable income: 7,500
Paid every two weeks or 26 weeks in a year
Based on 2007 Federal Income Tax Table for Single Taxpayer, Tim is under the tax range over $0 but not over $7,825. The tax is 10% of the amount over $0.
<span>1. Finds the tax rate for his income level =10 %
2. Enters the base amount = $7,500
3. Enters the amount of tax owed = $7,500 * 10% = $750
4. Divides by 26 = $750 / 26 = $28.85 tax withheld from biweekly wages.</span>
²⁰¹²C₂₀₁₁ = (2012)! / [(2011)! (2012-2011)!]
²⁰¹²C₂₀₁₁ = (2012)! / [(2011)! (1)!]
Simplify 2012! / (2011)! = 2012
²⁰¹²C₂₀₁₁ = (2012)! / (1)! = 2012
Answer:
The probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Step-by-step explanation:
According to the given statement we have to make five letter code from A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.
Thus the probability of picking the first letter M = 1/5
After that we require the sequence (not E, not E, not E) which is equal to:
= 3/4 * 2/3* *1/2
= 1/4
Now multiply 1/5 and 1/4
1/5 * 1/4
= 1/20
= 0.05
Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....
