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Papessa [141]
2 years ago
7

Lola measures three buttons for a shirt she is making. one button is 1/8 inch, one is 3/8 inch, and one is 1/4 inch. the button

hole on the shirt is 2/6 inch. which of the buttons will fit through the button hole ? explain
Mathematics
1 answer:
den301095 [7]2 years ago
7 0

Answer: The first and last button will fit through the button hole.

Step-by-step explanation:

since we have given that

Size of first button is given by

\frac{1}{8}\ inch

Size of second button is given by

\frac{3}{8}\ inch

Size of third button is given by

\frac{1}{4}\ inch

The size of hole of the shirt is given by

\frac{2}{6}\ inch=\frac{1}{3}\ inch

So, the size of button must be smaller than the size of hole in the shirt to get fit .

Since we first make the denominator same , as L.C.M. of all denominators i.e.(8,8,4,and 3) is 24

So, Size of first button is given by

\frac{1}{8}\ inch=\frac{1\times 3}{8\times 3}=\frac{3}{24}\ inch

Similarly, Size of second button is given by

\frac{3}{8}\ inch=\frac{3\times 3}{8\times 3}=\frac{9}{24}\ inch

Similarly, Size of third button is given by

\frac{1}{4}\ inch=\frac{1\times 6}{4\times 6}=\frac{6}{24}\ inch

And, The size of hole of the shirt is given by

\frac{1}{3}\ inch=\frac{1\times 8}{3\times 8}=\frac{8}{24}

As we can see that

\frac{3}{24}

Hence, the first and last button will fit through the button hole.


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Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x?
sergeinik [125]

Solving  RootIndex 3 StartRoot 8 EndRoot Superscript x we get =2^x

Step-by-step explanation:

We need to find equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x

Writing in mathematical form:

(\sqrt[3]{8})^x

Solving:

We know 8= 2x2x2= 2^3

and \sqrt[3]{x}=x^{\frac{1}{3}}

Applying these rules:

=((2^3)^{\frac{1}{3}})^x

=(2^{\frac{3}{3}})^x\\

=2^x

So, solving  RootIndex 3 StartRoot 8 EndRoot Superscript x we get =2^x

Keywords: Radical Expression

Learn more about Radical Expression at:

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8 0
1 year ago
8. In how many ways can a committee of four be selected from eight men and seven women if Miss Jones refuses to serve on the sam
____ [38]
If the exclusion of Miss Jones and Mr Smith serving together was not present, the are 15C4 = 1365 ways of selecting the committee.
Miss Jones can serve on the committee in the following ways:
a) with 3 men
b) with 2 men and another woman
c) with 1 man and 2 other women
d) with 3 other women.
Arrangement d) obviously presents no restrictions.
Arrangement a) has 7C3 ways excluding Mr Smith, and 8C3 ways if Mr Smith was included.
Arrangement b) has 7C2 * 6 ways excluding Mr Smith, and 8C2 * 6 ways if Mr Smith was included.
Arrangement c) has 7 * 6C2 ways excluding Mr Smith, and 8 * 6C2 ways if Mr smith was included.
The reductions in ways caused by the restriction are as follows:
a) 8C3 - 7C3 = 21 ways
b) 6(8C2 - 7C2) = 42 ways
c) 6C2 = 15 ways
The total reduction in the number of ways is: 21 + 42 + 15 = 78.
Therefore the total number of ways of selecting the committee, while observing the restriction, is 1365 - 78 = 1287 ways.
4 0
2 years ago
three positive numbers are in Arithmetic Progression (A.P). the sum of the squares of the three numbers is 155. while the sum of
Alecsey [184]
Given:
Three numbers in an AP, all positive.
Sum is 21.
Sum of squares is 155.
Common difference is positive.

We do not know what x and y stand for.  Will just solve for the three numbers in the AP.
Let m=middle number, then since sum=21, m=21/3=7
Let d=common difference.
Sum of squares
(7-d)^2+7^2+(7+d)^2=155
Expand left-hand side
3*7^2-2d^2=155
d^2=(155-147)/2=4
d=+2 or -2
=+2  (common difference is positive)

Therefore the three numbers of the AP are
{7-2,7,7+2}, or
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6 0
2 years ago
Lisa's test grades are 79, 89, and 90. there will be one more test this year. if lisa wants her test average to be at least 88,
erik [133]
For this case, what we are going to do first is to assume that all the exams are worth the same percentage of the final grade.
 We have then that Lisa's average grade point equation is:
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 Where,
 x: minimum note that lisa must obtain in the last exam.
 Clearing x we have:
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x = 94
 Answer:
 
the lowest grade she can get on her last test is:
 
x = 94
5 0
2 years ago
Two times the quantity of seven less than one-fourth of a number is equal to fout
djverab [1.8K]

The unknown number is 108.

Step-by-step explanation:

Step 1:

Assume the unknown number is x.

We create an equation from the given data.

One-fourth of the number is \frac{1}{4} x, seven less than one-fourth of the number is \frac{1}{4} x -7. Two times the quantity of seven less than one-fourth of a number is therefore 2(\frac{1}{4} x -7).

One-third of the number is \frac{1}{3} x, four more than one-third of the number is given by \frac{1}{3} x + 4.

Step 2:

We substitute both equations to determine the value of x.

2(\frac{1}{4} x -7) = \frac{1}{3} x + 4.

(\frac{2}{4} x -2(7)) = \frac{1}{3} x + 4.

\frac{1}{2} x -14 = \frac{1}{3} x + 4.

\frac{1}{2} x - \frac{1}{3} x = 4+14 = 18.

\frac{1}{6} x = 18.

x= 6(18) = 108.

So the unknown number is 108.

6 0
2 years ago
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