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Contact [7]
1 year ago
12

You are planning to hire a full-time electrician who will work 40 hours per week. If you plan on giving this new hire three week

s' vacation as a benefit, how many hours will this new hire work in twelve months?

Mathematics
1 answer:
tresset_1 [31]1 year ago
5 0

Option b) 1960 is the total number of hours the electrician worked.

<u>Step-by-step explanation:</u>

It is given that, the full-time electrician will work 40 hours per week.

So, we need to know the total number of hours he could work in twelve months which is one year.

Therefore, one year has a total of 365 days.

<u>To find the number of weeks in twelve months :</u>

Number of weeks = Total days in one year / 7 days of week

⇒ 365 / 7

⇒ 52.14 (approximately 52 weeks)

The number of weeks in twelve months is 52 weeks.

Now, of this 52 weeks, the three weeks are given as vacation.

The total number of weeks the electrician worked = 52 weeks - 3 weeks

⇒ 49 weeks.

The electrician worked for 49 weeks.

To calculate the total number of hours he worked = 49 weeks × 40 hours

⇒ 1960 hours.

Therefore, the  total number of hours the electrician worked is 1960 hours which is option b).

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2 years ago
If f(1) = 0 what are all the roots of the function f(x)=x^3+3x^2-x-3 use the remainder theorem.
ArbitrLikvidat [17]

Solution:

As we are given that f(1) = 0 .

It mean that (x-1) is one of the factor of the given equation.

Remainder theorem can be applied as below:

\frac{(x^3+3x^2-x-3)}{(x-1)}=\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}\\ \\\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}=\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)} \\\\\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)}=\frac{(x^2+4x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+4x+3)(x-1)}{(x-1)} =\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  =\frac{(x-1)(x+3)(x+1)}{(x-1)}

Hence the factors are (x-1),(x+3) and (x+1).

Hence the correct option is B.

5 0
2 years ago
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Dying for help please failing mathh
JulsSmile [24]
You might want to stick to at most five questions at once, makes it easier for the rest of us. :)

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Need clarification on anything?
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2 years ago
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The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv
Rina8888 [55]

Answer:

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=14.42 represent the sample mean

\mu population mean (variable of interest)

\sigma=6.95 represent the population standard deviation

n=36 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

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1 year ago
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