Ask question

Ask question

All categories

Law Incorporation [45]

1 year ago

7

In a competition, two people will be selected from four finalists to receive the first and second prizes. The prize winners will

be selected by drawing names from a hat. The names of the four finalists are Jim, George, Helen, and Maggie. The possible outcomes can be represented as follows: JG JH JM GJ GH GM HJ HG HM MJ MG MH Here, for example, JG represents the outcome that Jim receives the first prize and George receives the second prize. The event A is defined as follows: A = event that Helen gets first prize List the outcomes that comprise the event ~A (not A).

1 answer:

love history [14]1 year ago

4 0

Answer:

1. JG (Jim gets first prize, George gets second prize)

2. JH (Jim gets first prize, Helen gets second prize)

3. JM (Jim gets first prize, Maggie gets second prize)

4. GH (George gets first prize, Helen gets second prize)

5. GJ (George gets first prize, Jim gets second prize)

6. GM (George gets first prize, Maggie gets second prize)

7. MJ (Maggie gets first prize, Jim gets second prize)

8. MG (Maggie gets first prize, George gets second prize)

9. MH (Maggie gets first prize, Helen gets second prize)

Step-by-step explanation:

The question asks for the list of outcomes in the event "Not A". We are looking for the reverse or negative of Event A.

The above given list is the list of outcomes in the event where Helen DOES NOT get first prize.

You might be interested in

Sal was tired of waiting for Amir to show up at their meeting place, so he started running at an average speed of 4.5 mph withou

skelet666 [1.2K]

Let s and a represent the position of Sal and Amir respectively.

s=.75+4.5t and a=-.25+6.7t

When Sal catches Amir, s=a so we can say.

-.25+6.7t=.75+4.5t subtract 4.5t from both sides

-.25+2.2t=.75 add .25 to both sides

2.2t=1 divide both sides by 2.2

t=5/11 hours

t≈0.45 hours (to nearest hundredth of an hour)

3 0

2 years ago

Read 2 more answers

What is the multiplicative inverse of -0.7?

Verizon [17]

Answer:

The multiplicative inverse of -0.7 is -1/0.7

hope it helps

6 0

1 year ago

A random sample of 35 undergraduate students who completed two years of college were asked to take a basic mathematics test. The

lisov135 [29]

Answer:

$(75.1 -72.1) -1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= -1.96$

$(75.1 -72.1) +1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= 7.96$

And the confidence interval would be given by:

$-1.96 \leq \mu_1 -\mu_2 \leq 7.96$

And since the confidence interval contains the value 0 we have enough evidence to conclude that we don't have significant differences between the two means at 10% of significance.

Step-by-step explanation:

For this case we have the following info given :

$\bar X_1= 75.1$ represent the sample mean for the scores of the undergraduate students

$s_1 = 12.8$ represent the standard deviation for the undergraduate students

$n_1 =35$ the sample size for the undergraduate

$\bar X_2= 72.1$ represent the sample mean for the scores of the high school students

$s_2 = 14.6$ represent the standard deviation for the high school students

$n_2 =50$ the sample size for the high school

The confidence interval for the true difference of means is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

The degrees of freedom are given by:

$df=n_1 +n_2 -2= 35+50-2=83$

The confidence level is 90% and the significance level is $\alpha=0.1$ and $\alpha/2 =0.05$ then the critical value would be:

$t_{\alpha/2}= 1.99$

And replacing the info we got:

$(75.1 -72.1) -1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= -1.96$

$(75.1 -72.1) +1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= 7.96$

And the confidence interval would be given by:

$-1.96 \leq \mu_1 -\mu_2 \leq 7.96$

And since the confidence interval contains the value 0 we have enough evidence to conclude that we don't have significant differences between the two means at 10% of significance.

8 0

1 year ago

A student estimates the weight of astronauts on the moon by multiplying their weight by the decimal 0.16666....what fraction can

Elden [556K]

Let $x = 1.66666...$ ....(1)

Multiply both sides of equation (1) by 10.

$10x = 1.666666....$ .... (2)

Multiply both sides of equation (1) by 100.

$100x = 16.66666....$ ... (3)

Subtract equation (2) from equation (3)

$100x - 10x = 16.66666...- 1.66666...$

$90x = 15$

$x= \frac{15}{90} = \frac{1}{6}$

Hence, the required fraction form is $\frac{1}{6}$ .... Answer.

3 0

1 year ago

Read 2 more answers

The diameter of Circle Q terminates on the circumference of the circle at (0,3) and (0,-4). Write the equation of the circle in

Gnesinka [82]

First, determine the center of the circle by getting the midpoint of the points given for the circumference.
midpoint = ((0 + 0)/2, (3 + -4)/2)
midpoint (0, -0.5)
Then, we get the radius by determining the distance from either of the circumferential point to the center.
radius = √(0 - 0)² + (3 +4)² = 7
The equation for the circle would be,
x² + (y + 0.5)² = 7²

8 0

1 year ago